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AlekseyPX
4 years ago
15

Two loudspeakers, A and B, are driven by the same amplifier and emit sinusoidal waves in phase. The frequency of the waves emitt

ed by each speaker is 172 Hz. You are 8.00 m from speaker A. Take the speed of sound in air to be 344 m/s.
What is the closest you can be to speaker B and be at a point of perfectly destructive interference?
Physics
1 answer:
earnstyle [38]4 years ago
3 0

Answer:

Explanation:

Given that

Frequency =172Hz

Speed of sound =344m/s

Distance from A is 8m.

The wave length λ=v/f

Therefore, λ=344/172

λ=2m

for destructive interference, the path difference must be λ/2, the equation for destructive interference

Δr = (2n + 1) λ / 2

For the first interference n = 0

Δr = λ / 2

∆r=2/2

∆r=1m

the closest you can be to speaker B and be at a point of perfectly destructive interference is 1m

You might be interested in
How many orders of magnitude (powers of ten) is the distance to the moon greater than the distance across the Atlantic ocean?
kupik [55]

Answer:

The distance to the moon greater than the distance across the Atlantic ocean by an order of 1.

Explanation:

We have the average distance across the Atlantic ocean, d_i=3700\ mi

the average distance to the moon, d_m=238,900\ mi

The factor by which the distance to moon is greater than the width of Atlantic ocean:

f=\frac{d_m}{d_i}

f=\frac{238,900}{3700}

f=64.57

i.e.

the distance to the moon greater than the distance across the Atlantic ocean by an order of 1.

6 0
3 years ago
A basketball player can leap upward 0.43 m. how long does he remain in the air? use an acceleration due to gravity of 9.80 m/s2
MArishka [77]
From the equations of linear motion,
v² = u² + 2as where v is the final velocity, u is the initial velocity and a is the gravitational acceleration, and s is the displacement,
Thus, v² = u² -2gs, but v=0
hence, u² = 2gs
                = 2×9.81×0.43
                = 8.4366
            u = √8.4366
               =2.905 m/s
Hence the initial velocity is 2.905 m/s
 Then using the equation v= u +gt .
Therefore, v = u -gt. (-g because the player is jumping against the gravity)
but, v = 0
Thus, u= gt
Hence, t = u/g
              = 2.905/9.81
              = 0.296 seconds


3 0
3 years ago
A tuning fork is held over a resonance tube, and resonance occurs when the surface of the water is 12 cm below the top of the tu
Rainbow [258]

Answer:

786 Hz

Explanation:

Recall, the speed of sound is

v = 332 + 0.6t

Where t = 23°

v = 332 + 0.6(23)

v = 332 + 13.8

v = 345.8 m

Also, it is known that distance between two consecutive resonance length is half of the wavelength.

L2 - L1 = λ/2

34 - 12 = λ/2

λ/2 = 22

λ = 44 cm

Finally, remember that also

Frequency = speed/ wavelength

Frequency = 345.8/0.4

Frequency = 786 Hz

Therefore, the frequency of the tuning fork is 786 Hz

6 0
3 years ago
PHYSICS HELP PLEASE!! MUST SHOW MATH WORK!!
SVETLANKA909090 [29]

<u>Answer:</u>

1) Distance traveled by bird = 403 meter

2)Average speed = 1.66 km /hour

3) Zcceleration = 2 m/s^2

<u>Explanation:</u>

1)  Distance traveled = Speed * Time taken = 31 * 13 = 403 meter.

2)  Average speed = Total distance covered / Time taken for that distance to cover.

    Total distance covered = 2+0.5+2.5 = 5 km

    Time taken = 3 hours

     Average speed = 5/3 = 1.66 km /hour

3)    Acceleration is defined as the rate of change of velocity, so acceleration a = change in velocity/time.

  Change in velocity = 14 - 6 = 8 m/s

   Time = 4 seconds

   So acceleration = 8 / 4 = 2 m/s^2

6 0
3 years ago
An athlete is working out in the weight room. He steadily holds 50 kilograms above his head for 10 seconds. Which statement is t
ludmilkaskok [199]
Answer: the true statement form the given statements is “the athletes is not doing any work because he does not move weight”

7 0
3 years ago
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