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Kamila [148]
3 years ago
8

8. Which of the following is not a part of the pharynx?

Physics
2 answers:
Novosadov [1.4K]3 years ago
8 0

Answer:

C

Explanation:

Utrd5r7dt7ftf6d7tf6t756565t5tf5r55r755

Sladkaya [172]3 years ago
7 0
C is the correct answer.
You might be interested in
What is the frequency of blue light that has a wavelength of 473nm?
ankoles [38]

Answer:

6.34 x 19^14 Hz

Explanation:

Wavelength, λ = 473 nm = 473 x 10^-9 m

the relation between the frequency and the wavelength is given by

v = f x λ

where, v is the velocity of light in vacuum which is equal to 3 x 10^8 m/s.

So, f = v / λ

f = ( 3 x 10^8) / ( 473 x 10^-9)

f = 6.34 x 19^14 Hz

6 0
4 years ago
A coin is made of ______​
lys-0071 [83]

Answer:

coins made with the combination of copper zinc and Nickel

A cloth is made of fabrics

A towel is made from cotton

an umbrella is made up of fiberglass

a sweater is made up of wool

hope it helps

please mark me as the brainliest

5 0
3 years ago
"determine the average velocity of the particle over the time interval"
Softa [21]
This link should help you out https://quizlet.com/40330134/biomechanics-questions-flash-cards/

5 0
4 years ago
In the visible spectra of stars, absorption lines of hydrogen are produced when atoms are excited from n = 2 to higher levels (t
grigory [225]

Answer:

3. relatively high temperature, about 10,000 K, so that significant numbers of electrons are excited from the ground state, n = 1, to the first excited state, n = 2, but not too many of them have been ejected completely from the atoms

Explanation:

If hydrogen absorption lines are very strong in the visible spectrum of a particular star that means the population of electron in n = 2 is very high so on being exited they absorb radiation in Balmer series and give rise to absorption spectrum. The average temperature required to excite electron in hydrogen atom from n=1 to n = 2   is 10000K .

4 0
3 years ago
Given vectors D (3.00 m, 315 degrees wrt x-axis) and E (4.50 m, 53.0 degrees wrt x-axis), find the resultant R= D + E. (a) Write
Eva8 [605]

Answer:

  • R = ( 4.831 m , 1.469 m )
  • Magnitude of R = 5.049 m
  • Direction of R relative to the x axis= 16°54'33'

Explanation:

Knowing the magnitude and directions relative to the x axis, we can find the Cartesian representation of the vectors using the formula

\vec{A}= | \vec{A} | \ ( \ cos(\theta) \ , \ sin (\theta) \ )

where | \vec{A} | its the magnitude and θ.

So, for our vectors, we will have:

\vec{D}= 3.00 m \ ( \ cos(315) \ , \ sin (315) \ )

\vec{D}=  ( 2.121 m , -2.121 m )

and

\vec{E}= 4.50 m \ ( \ cos(53.0) \ , \ sin (53.0) \ )

\vec{E}= ( 2.71 m , 3.59 m )

Now, we can take the sum of the vectors

\vec{R} = \vec{D} + \vec{E}

\vec{R} = ( 2.121 \ m , -2.121 \ m ) + ( 2.71 \ m , 3.59 \ m )

\vec{R} = ( 2.121 \ m  + 2.71 \ m , -2.121 \ m + 3.59 \ m )

\vec{R} = ( 4.831 \ m , 1.469 \ m )

This is R in Cartesian representation, now, to find the magnitude we can use the Pythagorean theorem

|\vec{R}| = \sqrt{R_x^2 + R_y^2}

|\vec{R}| = \sqrt{(4.831 m)^2 + (1.469 m)^2}

|\vec{R}| = \sqrt{23.338 m^2 + 2.158 m^2}

|\vec{R}| = \sqrt{25.496 m^2}

|\vec{R}| = 5.049 m

To find the direction, we can use

\theta = arctan(\frac{R_y}{R_x})

\theta = arctan(\frac{1.469 \ m}{4.831 \ m})

\theta = arctan(0.304)

\theta = 16\°54'33''

As we are in the first quadrant, this is relative to the x axis.

3 0
3 years ago
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