All categories

1 year ago

What would be the magnitude of a

Physics

1 answer:

Pavlova-9 [17]1 year ago

7 0

The magnitude of a velocity vector is 60 m/s.

To find the magnitude, the given values are,

x - components = 36 m/s

y - components = 48 m/s

<h3>What is magnitude?</h3>

The term magnitude can be defined as “ quantity ”.
For instance, the magnitude can be used for describing about the comparison of speeds.

It can also be used to explain the distance travelled by an object or to explain the amount of an object in terms of its magnitude.
Magnitude of the velocity vector is total value which is square root of the value.

The magnitude of the vector can be,

| a | = √ ( x² + y² )

Substituting the values of x component and y component given,

= √ ( 36² + 48² )

= √ ( 1296 + 2304)

= √ 3600

= 60 m/s

The magnitude is found to be 60 m/s.

Hence, Option B is the correct answer.

Learn more about magnitude,

brainly.com/question/14452091

#SPJ1

You might be interested in

Bill is farsighted and has a near point located 121 cm from his eyes. Anne is also farsighted, but her near point is 74.0 cm fro

Arada [10]

Answer:

Explanation:

The lens equation is

1 / f = 1 / di + 1 / do

Where

f is focal length

di is the image distance

do is the object distance

Both Annie and Billy use a glass whose near point is 25cm

Then, the object distance is

do = 25 - 2 = 23cm

The have the same object distance.

Let find the vocal length of bills eye

Given that,

Bill near point is 121cm and distance of the glass from the eye is 2cm

Then,

Image distance of bill is

di_B = -(121-2) = -119cm

object distance do = 23cm

Then,

1 / f_B = 1 / di_B + 1 / do

1 / f_B = -1 / 119 + 1 / 23

1 / f_B = -119^-1 + 23^-1

1 / f_B = 0.0351

Then, f_B = 28.51 cm

Also, let find Annie focal length

Given that,

Annie near point is 74 cm and distance of the glass from the eye is 2cm

Then,

Image distance of Annie is

di_A = -(74-2) = -72cm

object distance do = 23cm

Then,

1 / f_A = 1 / di_A + 1 / do

1 / f_A = -1 / 72 + 1 / 23

1 / f_A = -72^-1 + 23^-1

1 / f_A = 0.02959

Then, f_A = 33.8 cm

Distance of object from the lens when Annie uses Billy glass

Then,

1 / f_B = 1 / di_A + 1 / do

1 / 28.51 = -1 / 72 + 1 / do

28.51^-1 = -72^-1 + do^-1

do^-1 = 28.51^-1 + 72^-1

do^-1 = 0.048964

do = 20.42 cm

Then, the object location from the eye will be, the eye is 2cm from the glass. Then,

do_A = 20.42 + 2 = 22.42cm

do_A = 22.42 cm

Distance of object from the lens when Billy uses Annie glass

Then,

1 / f_A = 1 / di_B + 1 / do

1 / 33.8 = -1 / 119 + 1 / do

33.8^-1 = -119^-1 + do^-1

do^-1 = 33.8^-1 + 119^-1

do^-1 = 0.03799

do = 26.32 cm

Then, the object location from the eye will be, the eye is 2cm from the glass. Then,

do_B = 26.32 + 2 = 28.32 cm

do_B = 28.32 cm

7 0

3 years ago

What minimum heat is needed to bring 150 g of water at 20 ∘c to the boiling point and completely boil it away? the specific heat

AnnZ [28]

Try this solution:

if given m=0.15 kg; t₁=20 °C; t₂=100 °C; c=4190 J/(kg*C); q=226*10⁴ J/kg., then

Q=Q₁+Q₂,

where Q₁=cm(t₂-t₁) and Q₂=q*m.

Finally,

Q=cm(t₂-t₁)+qm;

Q=4190*0.15*80+2240000*0.15=386280 J=<u>386.28 kJ</u>.

4 0

3 years ago

1) A tiger leaps horizontally from a 7.5 m high rock with a speed of 4.5 m/s. How far from

Artyom0805 [142]

The distance of tiger's leap from the base of rock is 5.58 m

It is a question of two dimensional motion

The time of motion in two dimensional motion is given by:

t= $\sqrt{2y/g}$

where y is the height and g is the acceleration due to gravity

y is given to be 7.5m and let us assume g to be 9.8 m/s^2

t = $\sqrt{2 * 7.5/9.8}$

= 1.24s

Using time and speed,

We know that distance is the product of speed and time,

Distance= speed x time

speed is given to be 4.5 m/s

distance from the base of rock = 4.5 x 1.24

= 5.58m

Hence the distance of tiger's leap from the base of rock is 5.58 m

Disclaimer:

The acceleration due to gravity is assumed to be 9.8 m/s^2

For further reference:

brainly.com/question/11213880?referrer=searchResults

#SPJ9

8 0

1 year ago

Suppose a 32-kg child sits in a playground swing

otez555 [7]

Answer:

Explanation:

6 0

3 years ago

The principal limitation of wind power is unpredictability. Please select the best answer from the choices provided

Lady_Fox [76]

<span>The correct answer is A: True. Although the ability to forecast weather has increased over the years, the ability to predict when and how much wind will occur at any given time and place is difficult. Weather conditions are subject to constant change and while some areas are known to have more wind than others, there is no guarantee about how much wind there will be as weather patterns vary in consistency.</span>

6 0

3 years ago

Read 2 more answers