Answer:
x=4
Step-by-step explanation:
x=0 is an undefined slope(straight line vertically)
We need the line to pass through the point (4,3)
So, we just take the x coordinate from the equation and make it also have an undefined slope.
x = 4
Answer:
The length of the longer ladder is 35 ft
Step-by-step explanation:
Please check the attachment for a diagrammatic representation of the problem
We want to calculate the length of the longer ladder ;
We make reference to the diagram
Since the two right triangles formed are similar. the ratios of their sides are equal;
Thus;
20/15 = 28/x + 15
20(x + 15) = 15(28)
20x + 300 = 420
20x = 420-300
20x = 120
x = 120/20
x = 6
So we want to calculate the hypotenuse of a right triangle with other sides 28ft and 21 ft
To do this, we use the Pythagoras’ theorem which states that square of the hypotenuse equals the sum of the squares of the two other sides
Let the hypotenuse be marked x
x^2 = 28^2 + 21^2
x^2 = 1,225
x = √1225
x = 35 ft
Answer:
- perimter of original rectangle = <u>17. 6 mm</u>
- side length of the enlarged rectangle = <u>23. 22 mm</u>
- perimeter of the enlarged rectangle = <u>95. 04 mm</u>
Step-by-step explanation:
<u>PERIMETER</u><u> </u><u>OF</u><u> </u><u>ORIGINAL</u><u> </u><u>RECTANGLE</u>
- Length of original rectangle = 4.5 mm
- Width of original rectangle = 4.3 mm
<em>perimeter = 2 × ( length + width)</em>
= 2 × ( 4.5 + 4.3)
= 2 × 8.8
= 17. 6 mm
<u>SIDE</u><u> </u><u>LENGTH</u><u> </u><u>OF</u><u> </u><u>ENLARGED</u><u> </u><u>RECTANGLE</u>
- Width of original rectangle = 4. 5 mm
- Width of enlarged rectangle = 24.3 mm
Enlargement factor = 24.3 / 4.5
= 5.4
- Length of original rectangle = 4.5 mm
- Enlargement factor = 5.4
Side length of enlarged rectangle
= original length × Enlargement factor
= 4.3 × 5.4
= 23. 22 mm
<u>PERIMTER OF ENLARGED RECTANGLE</u>
= 2 × ( enlarged ength + enlarged breadth)
= 2 × (23. 22 + 24. 3 )
= 95. 04 mm
Answer: 115 - (-30) = 115 + 30 = 145 degrees change
Step-by-step explanation:
Answer:
70 min
Step-by-step explanation:
If we take the hypothesis that by the end of the fifth day he had 5h20min drums practice then the remaining time to get to 7 hours practice time would be 1h40min.
