We need to find, how many 1/3s are in 1 2/3 the hexagon represents 1 whole.
In order to find that value, we need to divide 1 2/3 by 1/3.
Let us first convert 1 2/3 into improper fraction first.
1 2/3 = (1*3+2)/3 = 5/3.
Therefore,
5/3 ÷ 1/3.
Changing division sign into multiplication and flipping the second fraction, we get
5/3 × 3/1
3's cross out from top and bottom, we get
= 5.
<h3>Therefore, there are 5 times of 1/3s in 1 2/3.</h3>
The length of the first two sides of a triangle must be greater than the length of the last side. If the longest length were 18, the first two sides would be too short. 36-18=18, 18 is equal not greater than 18 which means the sum of the first two sides are too short.
Answer: The number of first-year residents she must survey to be 95% confident= 263
Step-by-step explanation:
When population standard deviation (
) is known and margin of error(E) is given, then the minimum sample size (n) is given by :-
, z* = Two-tailed critical value for the given confidence interval.
For 95% confidence level , z* = 1.96
As, = 8.265, E = 1
So, ![n= (\dfrac{1.96\times8.265}{1})^2 =(16.1994)^2\\\\= 262.42056036\approx263\ \ \ [\text{Rounded to the next integer}]](https://tex.z-dn.net/?f=n%3D%20%28%5Cdfrac%7B1.96%5Ctimes8.265%7D%7B1%7D%29%5E2%20%3D%2816.1994%29%5E2%5C%5C%5C%5C%3D%20262.42056036%5Capprox263%5C%20%5C%20%5C%20%5B%5Ctext%7BRounded%20to%20the%20next%20integer%7D%5D)
Hence, the number of first-year residents she must survey to be 95% confident= 263
Substitute= -5–2 x 2
solve= 10x2
=20
Here is your answer. Good luck!
