How does one determine the identity and structure of an unknown compound? This is not a trivial task. Modern x-ray and spectroscopic techniques have made the job much easier, but for some very complex molecules, identification and structure determination remains a challenge. In addition to spectroscopic information and information obtained from other instrumental methods, chemical reactions can provide useful structural information, and physical properties can contribute significantly to confirming the identity of a compound.
In this experiment, you will be asked to identify an unknown liquid, which will be either an alcohol, aldehyde, or ketone. Identification will be accomplished by carrying out chemical tests, called classification tests, preparing a solid derivative of the unknown and determining its melting point (MP), making careful observations, and analyzing the NMR spectrum of the unknown.
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The wire could break when your on it. Another one this is kind of personal if you don't stop yourself on the zip line you could slam off the rope or post.
Mixtures are impure substances composed of two or more substances physically combined.
<h3>What are mixtures?</h3>
Mixtures are substances that are composed of two or more substances physically combined.
Mixtures are one of the different types of substances which are composed of matter.
The classification of matter by type of substance is as follows:
- Matter - Pure and impure substances or mixtures
- Pure substances - elements and compounds
- Mixtures: homogenous and heterogenous
In conclusion, substances can be classified into either pure substances or mixtures.
Learn more about substances and mixtures at: brainly.com/question/1867365
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Answer:
a pure substance or a compound
Answer:
100 grams of C-14 decays to 25 grams in 11,460 years.
The C-14 isotope is only useful for dating fossils up to about 50,000 years old
If an ancient bone contains 6.25% of its original carbon, then the bone must be 22,920 years old.
Explanation:
We already know that the half life of C-14 is 5,730 years. After the first half life, we have 50 grams remaining. This takes 5,730 years. After the second half life (11,460 years now gone) we have 25 grams of C-14 left.
If a fossil material is older than 50,000 years an undetectable amount of 14C is left in the sample hence Carbon-14 is no longer suitable for dating the sample.
From;
0.693/5730 = 2.303/t log (No/0.0625No)
Where;
t = time taken and No = initial amount of C-14
0.693/5730= 2.77/t
t = 22,920 years
