Answer:
First start with the ones we know
Explanation:
1. small - gene
2.chromosome - chromosomes contain genes so they must be bigger
3.dna- is all the chromosomes (genetic material)
A couple of homologous chromosomes, or homologs, are a set of one maternal and one paternal chromosome that pair up with each other inside a cell
a pair - so must be bigger than one chromosome
1. small - gene
2.chromosome - chromosomes contain genes so they must be bigger
3. homologus pair
4.dna- is all the chromosomes (genetic material)
now 5.
A gene consists of enough DNA to code for one protein, and a genome is simply the sum total of an organism's DNA. DNA is long and skinny, capable of contorting like a circus performer when it winds into chromosomes.
1. small - gene
2.chromosome - chromosomes contain genes so they must be bigger
3. homologus pair
4.dna- is all the chromosomes (genetic material)
5. genome - all the DNA
Cell
Nucleus
DNA
Chromosome
Gene
Answer:
a) Keq = 4.5x10^-6
b) [oxaloacetate] = 9x10^-9 M
c) 23 oxaloacetate molecules
Explanation:
a) In the standard state we have to:
ΔGo = -R*T*ln(Keq) (eq.1)
ΔGo = 30.5 kJ/moles = 30500 J/moles
R = 8.314 J*K^-1*moles^-1
Clearing Keq:
Keq = e^(ΔGo/-R*T) = e^(30500/(-8.314*298)) = 4.5x10^-6
b) Keq = ([oxaloacetate]*[NADH])/([L-malate]*[NAD+])
4.5x10^-6 = ([oxaloacetate]/(0.20*10)
Clearing [oxaloacetate]:
[oxaloacetate] = 9x10^-9 M
c) the radius of the mitochondria is equal to:
r = 10^-5 dm
The volume of the mitochondria is:
V = (4/3)*pi*r^3 = (4/3)*pi*(10^-15)^3 = 4.18x10^-42 L
1 L of mitochondria contains 9x10^-9 M of oxaloacetate
Thus, 4.18x10^-42 L of mitochondria contains:
molecules of oxaloacetate = 4.18x10^-42 * 9x10^-9 * 6.023x10^23 = 2.27x10^-26 = 23 oxaloacetate molecules
I think it’s b?! have a good day!
Answer:
Photons
Explanation:
A hot object emits photons of various energies, which propagate outwards from the object. When they hit another object, the photons can be absorbed, giving up their energy to the second object. This causes the atoms/molecules etc. to giggle around, rotate, vibrate etc., with the result that the second object heats up.
Answer:
C(btw this could be wrong)
Explanation:
