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lapo4ka [179]
2 years ago
6

-19-(k + 7) + 10k I need help on this you have to simplify the expression

Mathematics
1 answer:
Step2247 [10]2 years ago
3 0

Answer: =9k−26

Step-by-step explanation:

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Researchers report that on average freshman who live on campus gain 15 pounds during their first year in college. You survey 10
neonofarm [45]

Answer: 1.460

Step-by-step explanation:

Given : Researchers report that on average freshman who live on campus gain 15 pounds during their first year in college.

Let \mu represents the population mean .

Then, the set of hypothesis will be:-

H_0: \mu=15

H_a:\mu\neq15

We assume that this is normal distribution.

Sample size : n = 10, which is a small sample (n<30) ,s o we use t-test.

Sample mean : \overliene{x}=16.2\ lbs

Standard deviation : \sigma=2.6

The test statistic for population mean for small sample is given by :-

t=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

t=\dfrac{16.2-15}{\dfrac{2.6}{\sqrt{10}}}=1.45951276623\approx1.460

Hence , the value of test statistic = 1.460

4 0
3 years ago
Simplify <br> (^3)x4<br> Easy 30 points
aleksklad [387]

Answer:

=81

Step-by-step explanation:

\left(-3\right)^4

Use exponent rule \left(-a\right)^n=a^n:

=3^4

=81

5 0
2 years ago
Read 2 more answers
For the following​ case, assume that the population standard deviation is known and decide whether use of the​ z-interval proced
Ray Of Light [21]

Answer:

B. It is reasonable to use the? z-interval procedure in this case? since, although the sample is small? (size less than? 15), the variable under consideration is very close to being normally distributed.

Step-by-step explanation:

answer b is considered to be correct because we know that the population is normal and the standard deviation is known, which allows using the interval z, the answer A is not correct because although the option to use the interval z is given, which is correct, the large sample is not favored, the answer C and D are incorrect because they both reject the use of the z interval and in d it is further rejected that although there is a normal distribution the sample is not, which is false

8 0
3 years ago
Again(sorry) did anyone know 96 and 97
vladimir2022 [97]
96: 

sugar: 1,2,3,4,5,6
flour:2,4,6,8,10,12

97:

yellow:3,6,9,12,15,18
blue:1,2,3,4,5,6
7 0
2 years ago
Read 2 more answers
Solve the equation algebraically:<br> 10<br> 1<br> X= 7<br> I<br> I need an explanation too
Snowcat [4.5K]
Elaborate please for
3 0
2 years ago
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