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VLD [36.1K]
3 years ago
9

When converting from a smaller to a larger unit of measurement, you move the _______ to the right. A. second number B. ratio C.

exponent D. decimal point
Physics
2 answers:
viktelen [127]3 years ago
7 0
The answer to your question is D
Ghella [55]3 years ago
5 0

Answer:

The correct answer is D. decimal point.

Explanation:

The question is wrong. It should be :

When converting from a smaller to a larger unit of measurement, you move the _______ to the left.

In order to convert from a smaller to a larger unit of measurement what we need to move is the decimal point to the left. Let's see an example :

We have the two following units

''g'' which is grams and ''kg'' which is kilograms.  

We know that the grams are a smaller unit of measurement that kilograms.

We also know the relationship :

1kg=1000g

For example if we want to convert 1500g to kilograms :

(1500g).(\frac{1kg}{1000g})=1.5kg

What we have done is that we divided the number ''1500'' by ''1000''.

This is equal to move the decimal point three places to the left ⇒

1500g=1.5kg

The correct answer is D. decimal point

You might be interested in
Calculate the force which will produce an extension of 0.30mm in a steel wire with a length of 4.0m and a cross section area of
Anna [14]

Given data:

* The extension of the steel wire is 0.3 mm.

* The length of the wire is 4 m.

* The area of cross section of wire is,

A=2\times10^{-6}m^2

* The young modulus of the steel is,

Y=2.1\times10^{11}\text{ Pa}

Solution:

The young modulus of the steel in terms of the force and extension is,

Y=\frac{F\times l}{A\times dl}

where F is the force acting on the steel wire,, l is the original length of the wire, dl is the extension of the wire, and A is the area,

Substituting the known values,

\begin{gathered} 2.1\times10^{11}=\frac{F\times4}{2\times10^{-6}\times0.3\times10^{-3}} \\ F=0.315\times10^2\text{ N} \\ F=31.5\text{ N} \end{gathered}

Thus, the force which produce the extension of 0.3 mm of the steel wire is 31.5 N.

7 0
1 year ago
Please answer!
Elden [556K]
I can confirm, your answer is 800J (Or 800 Joules)!

I just took the test and this was the correct answer :)
4 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASAP
kirill [66]

Answer:

55.44.4 hjejjejjejej be

Explanation:

hehhehebebebbebeb

4 0
3 years ago
A bicycle rides in a straight line at 1 km at 10<br> km/h and then another 1 km at 25 km/h
elixir [45]

Answer:

17.5

Explanation:

1+1=2

2/2=1

10+25=35

35/2=17.5

3 0
3 years ago
A girl is sitting in a sled sliding horizontally along some snow (there is friction present). The mass of the girl is 28.4 kg an
Luden [163]

Answer:

-13,594 J

Explanation:

First of all, we have to find the acceleration of the girl+sled system. This can be found by using Newton's second law of motion:

F=ma

where:

F = -96 N is the net force (the force of friction) acting on the system

m = 28.4+15.3 = 43.7 kg is the total mass of the girl and the sled

a is their acceleration

Solving for a,

a=\frac{F}{m}=\frac{-96}{43.7}=-2.2 m/s^2

The negative sign means the sled is slowing down.

Now we can find the displacement of the sled during the deceleration phase, by using the suvat equation:

s=ut+\frac{1}{2}at^2

where

u = 41.8 m/s is the initial velocity

t = 3.76 s is the time

a=-2.2 m/s^2 is the acceleration

So,

s=(41.8)(3.76)+\frac{1}{2}(-2.2)(3.76)^2=141.6 m

Now we can find the work done by friction on the sled, which is given by:

W=Fs

where

F = -96 N is the force of friction

s = 141.6 m is the displacement of the sled+girl system

Solving,

W=(-96)(141.6)=-13,594 J

where the negative sign means the force is opposite to the displacement.

8 0
3 years ago
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