Answer:

Explanation:
The question: What is the net force exerted by these two charges on a third charge q_3 = 47.0 nC placed between q_1 and q_2 at x_3 = -1.240 mm ?
<u>Your answer may be positive or negative, depending on the direction of the force.</u>
Solution:
The coulomb force is given by the equation

where
is the separation between the charges
and
.
Now, in our case



The separation between charges
and
is

Therefore, the force between them is

and it is directed in the negative x-direction.
The separation between charges
and
is

therefore, the force between them is

Therefore the total force on charge
is

D. Pickup truck because it's heavy and it gained more momentum
Answer:
Explanation:
The process is isothermic, as P V = constant .
work done = 2.303 n RT log P₁ / P₂
= 2.303 x 5 / 29 x 8.3 x 303 log 2 / 1 kJ
= 300.5k J
This energy in work done by the gas will come fro heat supplied as internal energy is constant due to constant temperature.
heat supplied = 300.5k J
specific volume is volume per unit mass
v / m
pv = n RT
pv = m / M RT
v / m = RT / p M
specific volume = RT / p M
option B is correct.
The centripetal acceleration = 236.63 m/s²
The force = 17.98 N
<h3>Further explanation</h3>
Given
mass = 76 g = 0.076 kg
r = 1.5 m
f = 2 rps = 2 rotation per second
Required
The centripetal acceleration
The Force tension
Solution
Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle

F = centripetal force, N
m = mass, Kg
v = linear velocity, m / s
r = radius, m
The speed that is in the direction of the circle is called linear velocity
Can be formulated:

r = circle radius
f = rotation per second (RPS)
The linear velocity : 2 x 3.14 x 1.5 x 2 =18.84 m/s
The centripetal acceleration : ac = v²/R = 236.63 m/s²
The force : F = m x ac = 0.076 x 236.63 = 17.98 N
Answer: The volume is: " 1.430 cm³ " .
_____________________________
Explanation:
________________________
Volume, " V = ? ; (unknown, we need to solve for this).
Density, "D = 19.32 g / cm³ ;
mass , "m" = 27.63 g ;
_____________________________________________
The formula for density is:
____________________________________________
D = m / V ; Divide each side of the equation by: "(1/m)" ;
to isolate " V" on one side of the equation; and to solve for "V" ;
____________________________________________
1/m)*D = (1/m) * (m / V) ;
_______________________________
to get:
_______________________________
D/m = ; ↔ 1 / V ; Take the reciprocal of EACH SIDE; to isolate "V" on each side of the equation:
_____________________________
m / D = V/1 ↔ V = m / D ;
_____________________________
V = m / D ;
_______________________________
Now, plug in our given values for mass, "m" ; and Density, D"; to solve for "Volume, V " ;
_____________________________________
V = m / D = (27.63 g) ÷ (<span>19.32 g / cm</span>³) ;
= (27.63 g) * (1 cm³ / 19.32 g) ;
= (27.63 ÷ 19.32) cm³ ;
= 1.4301242236024845 cm³ ;
→ Round to "4 significant figures" ;
= 1.430 cm³ .
____________________________________________
The volume is: " 1.430 cm³ " .
______________________________________________