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larisa [96]
4 years ago
14

D=1/2at^2 solve for a

Physics
1 answer:
nignag [31]4 years ago
4 0

Answer:

a = 2d / t²

Explanation:

d = ½ at²

Multiply both sides by 2:

2d = at²

Divide both sides by t²:

a = 2d / t²

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With the switch open, roughly what must be the resistance of the resistor on the right for the current out of the battery to be
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Question:

Assumptions

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Answer:

For the current out of the battery to be the same as when the switch was opened with the switch closed, the resistance on the resistor on the right must be approximately 20/3 Ω

Explanation:

We note that the switch in the assumption is on the same line as the 20 Ω resistor.

With a voltage of 24 V, and the switch closed, we have;

Total resistance =  \frac{1}{\frac{1}{10} +\frac{1}{20} } = \frac{20}{3} \Omega

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Resistance on the right = Initial total resistance =  \frac{20}{3} \Omega

Therefore, with the switch opened, the resistance on the resistor on the right must be approximately equal to the resultant resistance of the two resistances in parallel.

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3 years ago
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