Answer:
2 touchdowns, 3 field goals
Step-by-step explanation:
The number of touchdowns cannot be more than 3, so it is relatively easy to find the solution by trial and error.
23 is not divisible by 3, so 0 touchdowns is not a solution
23 -7 = 16 is not divisible by 3, so 1 touchdown is not a solution
23 -14 = 9 is divisible by 3, so 2 touchdowns and 3 field goals is a solution
21 -21 = 2 is not divisible by 3, so there is only one solution.
Subtract 2x from both sides then you’d have -7x+4=16 Then you subtract 4 from both sides and you’d get -7x=12. Next you divide both side by -7 so x=1.75 rounded to the nearest hundredth.
Answer:
Lower and upper quartiles
Step-by-step explanation:
The box starts at lower quartile, ends at upper quartile
