88.5% is the correct answer according to my calculations.
Answer:
(a) 1.92 moles of Bi produced.
(b) 80.6 grams
Explanation:
Balanced equation: Bi2O3(s) + 3C(s) → 2Bi(s) + 3CO(g)
1st find moles of Bi2O3:
Bi2O3 has Mr of 466 and mass of 447 g
2nd find moles of Bi:
Bi2O3 : 2Bi
→ 1 : 2 ------ this is molar ratio.
→ 0.959227 : (0.959227)*2
→ 0.959227 : 1.91845
→ 0.959227 : 1.92
Therefore 1.92 moles of Bi was produced.
3rd Find moles of 3CO:
Bi2O3 : 3CO
1 : 3
0.959227 : (0.959227 )*3
0.959227 : 2.87768
3CO has 2.87768 moles and we know the Mr is 28.
g
Therefore 80.575 grams of CO was produced.
Lead is heavier and more resistant. Plastic foam is light and can easily be broken
Answer:
3(NH₄)₂SO₄(aq) + 2Cr(NO₃)₃(aq) → 6NH₄NO₃(aq) + Cr₂(SO₄)₃(s)↓
Explanation:
- Aqueous ammonium sulfate reacts with aqueous chromium(III) nitrate, forming aqueous ammonium nitrate and a precipitate of chromium(III) sulfate according to the balanced equation:
<em>3(NH₄)₂SO₄(aq) + 2Cr(NO₃)₃(aq) → 6NH₄NO₃(aq) + Cr₂(SO₄)₃(s)↓</em>
3.0 moles of ammonium sulfate reacts with 2.0 moles of chromium(III) nitrate, forming 6.0 moles of ammonium nitrate and 1.0 mole of chromium(III) sulfate.
When 1. 0 l of 0. 00010 m NaOH and 1. 0 l of 0. 0014 m mgso4 are mixed, there will be no precipitate formed.
<h3>What is a precipitate?</h3>
The precipitate is the solid concentration of a substance that is collected over a solution.
First, we determine the concentration of magnesium and hydroxide
(Mg2+) = 7.00 × 10⁻⁴
(OH−) = 5.00 × 10⁻⁵
Now, we calculate the solubility quotient
Qc = (Mg2+) (OH−) ²
Qc = 7.00 × 10⁻⁴ x (5.00 × 10⁻⁵)²
Qc = 1.75 x 10⁻¹²
The solubility product of the magnesium hydroxide is 1.80 x 10⁻¹¹ which is more than the solubility quotient. Thus, there will be no precipitate form.
Thus, there will be no precipitate formed because the solubility quotient we calculated is less than the solubility product.
To learn more about precipitate, refer to the below link:
brainly.com/question/16950193
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