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Alexxx [7]
2 years ago
11

The morning temperature in a city is 41°F. If a sunny, mild day is forecast, which temperature is most likely for 2:00 p.m.?

Chemistry
1 answer:
romanna [79]2 years ago
5 0

Answer:

huh

Explanation:

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ou discover that the complex decomposes in water. When 0.1000 g of the complex is dissolved in water with excess NaHg(SCN)4, all
Eduardwww [97]

Answer:

6.28x10⁻³ g

Explanation:

First we convert 0.1102 grams of CoHg(SCN)₄ into moles, using its <em>molar mass</em>:

  • 0.1102 g ÷ 491.9 g/mol = 2.24x10⁻⁴ mol CoHg(SCN)₄

There is 1 Co mol per CoHg(SCN)₄ mol, meaning there's also 2.24x10⁻⁴ moles of Co.

We now <u>convert 2.24x10⁻⁴ moles of Co into grams</u>, using its <em>molar mass</em>:

  • 2.24x10⁻⁴ mol Co * 28.01 g/mol = 6.28x10⁻³ g
7 0
3 years ago
1.) ____ N2 + ____ H2 ---------&gt;___NH3
kykrilka [37]

Answer:

N2 + 3H2 ------> 2NH3

2AlBr + 3K2SO4------> 6KBr + Al(SO4)3

8 0
2 years ago
If 35 ml of 6.0 m h2so4 was spilled, calculate the minimum mass of nahco3 that must be added to the spill to neutralize the acid
belka [17]

The balanced equation between the H_2SO_4 and NaHCO_3 is:

H_2SO_4+2NaHCO_3\rightarrow Na_2SO_4+2CO_2+2H_2O

Formula of molarity is:

Molarity = \frac{Moles of solute}{Volume of solution in Liters}

Molarity = 6.0 M, Volume = 35 mL = 0.035 L

Substituting the values,

6 = \frac{Moles of solute}{0.035}

Moles of solute = 0.035 L\times 6 mol/L = 0.21 mole

So, number of moles of H_2SO_4 is 0.21 mole.

From the balanced equation it is clear that for 1 mole of H_2SO_4, 2 moles of NaHCO_3 are required.

Hence, 0.21 mole of H_2SO_4  = 2\times 0.21 mole = 0.42 mole of NaHCO_3

Molar mass of NaHCO_3 = 84.007 g/mol

So, the mass of NaHCO_3 = 84.007 g/mol \times 0.42 mol = 35.283 g




6 0
3 years ago
What is the three properties of matter
Sav [38]
A solid, a liquid or a gas.
6 0
3 years ago
Read 2 more answers
Anyone know ?? I need help with this
nevsk [136]

Answer:

A

Explanation:

Because the amount of electrons in the outer shell can be a maximum of 8

Hope this helps

6 0
3 years ago
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