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3 years ago

What would happen to the position of the equilibrium when the following changes are made to the reaction below?

Chemistry

2 answers:

love history [14]3 years ago

6 0

Answer:

I don't know good luck

Explanation:

crimeas [40]3 years ago

6 0

Any impact on pressure will only affect gas molecules. So in this question the reactant has 0 gas molecules and the products have 1 gas molecule (the O2 molecule).

This means when you decrease the pressure the equilibrium will shift in order to oppose this change.

As you decreased the pressure it will move to the reaction that will increase the pressure back to equilibrium. So if you decrease pressure the equilibrium will shift to the right hand side (forward reaction) to oppose the change in pressure and a higher yield of Hg(l) and O2(g) will be produced.

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Explain how sodium and calcium react with water. explain with equations

34kurt

Reaction of sodium with water

Sodium metal reacts rapidly with water to form a colourless solution of sodium hydroxide (NaOH) and hydrogen gas (H2). The resulting solution is basic because of the dissolved hydroxide. The reaction is exothermic. During the reaction, the sodium metal may well become so hot that it catches fire and burns with a characteristic orange colour. The reaction is slower than that of potassium (immediately below sodium in the periodic table), but faster than that of lithium (immediately above sodium in the periodic table).

2Na(s) + 2H2O → 2NaOH(aq) + H2(g)

4 0

3 years ago

What happens when

jolli1 [7]

Answer:

a i think but idk

Explanation:

3 0

3 years ago

!!20 Points!!

elena-14-01-66 [18.8K]

Answer:Tungsten changes oxidation numbers +6 to zero

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Explanation:

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3 years ago

Which topic is Eunice's project most likely about?

otez555 [7]

Answer:

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6 0

4 years ago

A car with a mass of 1,200 kilograms is moving around a circular curve at a uniform velocity of 20 meters per second. The centri

Helga [31]

The answer is 80 m.

Centripetal force (F) is a force that makes body move around a circular curve. The unit of force is N (N = kg * m/s²).
It can be represented as:
$F= \frac{m* v^{2} }{r}$
where:
m - mass
v - velocity
r - radius of the curve

We have:
m = 1,200 kg
V = 20 m/s
F = 6,000 N = 6,000 kg * m/s²

We need radius of the curve:
r = ?

So, if <span> $F= \frac{m* v^{2} }{r}$ , then:
</span> $r= \frac{3* v^{2} }{F}$
⇒ $r = \frac{1200 kg * (20m/s)^{2} }{6000 kg*m/s^{2} }$
⇒ $r= \frac{1200*400*kg*m^{2}*s^{2} }{6000kg*m/s^{2} }$
⇒ $r= \frac{480,000m}{6000}$
⇒ $r=80m$

6 0

3 years ago