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2 years ago

What would happen to the position of the equilibrium when the following changes are made to the reaction below?

Chemistry

2 answers:

love history [14]2 years ago

6 0

Answer:

I don't know good luck

Explanation:

crimeas [40]2 years ago

6 0

Any impact on pressure will only affect gas molecules. So in this question the reactant has 0 gas molecules and the products have 1 gas molecule (the O2 molecule).

This means when you decrease the pressure the equilibrium will shift in order to oppose this change.

As you decreased the pressure it will move to the reaction that will increase the pressure back to equilibrium. So if you decrease pressure the equilibrium will shift to the right hand side (forward reaction) to oppose the change in pressure and a higher yield of Hg(l) and O2(g) will be produced.

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What would be the formula of the compound iron (III) phosphide?

irina1246 [14]

7 0

3 years ago

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The mole fraction of CO2 in a certain solution with H2O as the solvent is 3.6 × 10−4. What is the approximate molality of CO2 in

nataly862011 [7]

Answer: C) 0.020 m

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molality=\frac{n\times 1000}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent in g

Mole fraction of $CO_2$ is = $3.6\times 10^{-4}$ i.e. $3.6\times 10^{-4}$ moles of $CO_2$ is present in 1 mole of solution.

Moles of solute $(CO_2)$ = $3.6\times 10^{-4}$

moles of solvent (water) = 1 - $3.6\times 10^{-4}$ = 0.99

weight of solvent = $moles\times {\text {Molar mass}}=0.99\times 18=17.82g$

Molality = $\frac{3.6\times 10^{-4}\times 1000}{17.82g}=0.020$

Thus approximate molality of $CO_2$ in this solution is 0.020 m

5 0

3 years ago

The elements least likely to form bonds are found in which group?

taurus [48]

Answer:

Noble gases are a unique set of elements in the periodic table because they don't naturally bond with other elements.

Explanation:

HAVE A GOOD DAY!

4 0

2 years ago

Balance this redox reaction occurring in acidic media:

Lelu [443]

Add 7 water atom to the right hand side to adjust the quantity of oxygen. Increase Cr(+3) by two to adjust the quantity of Cr. Duplicate Cl-by two to adjust the quantity of chlorine molecules.
Cr2O7[2-](aq) +2 Cl[-](aq) < - >2 Cr[3+] (aq) + Cl2(g)+7H2O
Presently adjust that charges.
you have - 4 charges on the left hand side, while +18 charges on the right hand side, there for include 14H+ the left hand side to adjust the charges
Cr2O7[2-](aq) +2 Cl[-](aq)+14H+ < - >2 Cr[3+] (aq) + Cl2(g)+7H2O
take note of that the oxidation number of hydrogen in water is +1

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3 years ago

Which element does not have the same number of electrons in its outermost shell as the other elements in its group?(1 point)

Natalija [7]

Answer:

Helium

Explanation:

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3 years ago