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marishachu [46]
3 years ago
11

Which expressions equals 9^3 sqrt 10

Mathematics
1 answer:
matrenka [14]3 years ago
5 0
5^3 Sartre 10 + 4^3 sqrt 10
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The manufacturer of an airport baggage scanning machine claims it can handle an average of 530 bags per hour. (a-1) At α = .05 i
fenix001 [56]

Answer:

Null hypothesis:\mu \geq 250        

Alternative hypothesis:\mu < 250  

p_v =P(t_{15}    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not significantly lower than 530 at 5% of significance.      

Step-by-step explanation:

1) Data given and notation        

\bar X=510 represent the mean for the sample    

s=50 represent the standard deviation for the sample  

n=16 sample size        

\mu_o =530 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.      

t would represent the statistic (variable of interest)        

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.        

We need to conduct a hypothesis in order to determine if the claim thet the handle on average is 530 bags per hour:      

Null hypothesis:\mu \geq 530        

Alternative hypothesis:\mu < 530        

We don't know the population deviation and the sample size is lees than 30, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:        

t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)        

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic        

We can replace in formula (1) the info given like this:        

t=\frac{510-530}{\frac{50}{\sqrt{16}}}=-1.60        

4) Calculate the critical value

We need to begin calculating the degrees of freedom

df=n-1=16-1=15

The critical value for this case would be :

P(t_{15}

The value of a that satisfy this on the normal standard distribution is a=-1.75 and would be the critical value on this case zc=-1.75

5) Calculate the P-value        

Since is a one-side upper test the p value would be:        

p_v =P(t_{15}    

6) Conclusion        

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not significantly lower than 530 at 5% of significance.      

8 0
2 years ago
Plz help I am timed
kramer

Answer:

C

Step-by-step explanation:

3 0
3 years ago
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What is decimals -4.8(5.3)
bearhunter [10]

Answer:

-25.44

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the vertex of the equation y = -x 2 + 10x - 28?
Roman55 [17]

Answer:

(5,-3)

Step-by-step explanation:

Rewrite the equation in vertex form

y =-(x-5)^2 - 3

You take the value of -5 (that would be your x value) and change it to the opposite sign -> +5

Then you take -3 (that would be your y value) and take it as it is

therefore the answer is (5, -3)

3 0
3 years ago
Solve for : can someone plss help I dont remember how to solve this ​
ArbitrLikvidat [17]

Answer:

x = 18

Step-by-step explanation:

7x - 26 = 5x + 10

7x - 26 - 5x - 10 =0

2x - 36 = 0

2x = 36

x = 18

7 0
3 years ago
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