Answer:
Distance, S = 110 meters
Explanation:
Given the following data;
Initial velocity = 15 m/s
Acceleration = 4 m/s²
Time = 5 seconds
To find the distance covered, we would use the second equation of motion;
Where;
S is the distance covered or displacement of an object.
u is the initial velocity.
a is the acceleration.
t is the time.
Substituting the values into the equation, we have;
Distance, S = 110 meters
The central maximum
extends to the first minimum on either side.
So the first minimum
occurs at <span>3cm / 2 = 1.5cm = 0.015m to the side from the center of the
central maximum. </span>
<span>Now using the formula,
λ = a(y/L)</span>
Where a is the width of
the slit, y = distance of first minimum from center, L = distance of screen
from slit, and λ = wavelength of the light that strikes a single slit at normal
incidence which is unknown here.<span>
a = L x λ/y
a = 1.80 m x (λ / 0.015 m)
a = 120 λ </span>
<span>Use the value of λ for
any light and you get the width of slit.</span>
Answer:
Magnetic Forces on Moving Charges. The magnetic force on a free moving charge is perpendicular to both the velocity of the charge and the magnetic field with direction given by the right hand rule.
Answer:
h = 69.6 m
Explanation:
Data:
- Vo = 25 m/s
- t = 2.0 s
- g = 9.8 m/s²
- h = ?
Formula:
Replace and solve:
The building has a height of <u>69.6 meters.</u>
Greetings.