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wolverine [178]
3 years ago
13

Scientists have recently discovered one the smallest stars on record. How long will this star last

Physics
2 answers:
jok3333 [9.3K]3 years ago
4 0

Answer:

The correct answer is B.

Explanation:

Stars start their lives being dense clouds of gas and dust. After a star is formed, it begins to burn hydrogen and transform it into helium. Once the hydrogen is depleted, new stages of nuclear combustion begin, such as burning helium to obtain heavier elements. This stage is shorter in larger stars since the greater the mass of a star, the greater the temperature in its nucleus and the greater the rate of fusion of hydrogen into helium, with which the fuel is depleted more quickly.

Have a nice day!

Free_Kalibri [48]3 years ago
3 0

Answer:

I am thinking that it's c

Explanation:

hope that helps

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After six half-lives, what percentage of a radioactive sample will remain?
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A train travelled from city a to city b. For the first 14hours,it travelled at an average speed of 120km/h. For the 10 hours, it
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Explanation:

distance covered in the first part of journey : 120×14 = 1680km

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hope this helps you.

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3 years ago
What are the correct units for energy and work
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Answer:

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Explanation:

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5 0
2 years ago
"an open tank has the shape of a right circular cone. the tank is 6 feet across the top and 5 feet high. how much work is done i
Nonamiya [84]

Answer:

The amount of workdone by in emptying the tank by pumping the water over the top edge is \mathbf{ 1169.99 \pi \ ft-lbs}

Explanation:

Given that the tank is 6 feet across the top and 5 feet high.

Using the similar triangles.

\dfrac{3}{5}  = \dfrac{r}{y}

5r = 3y

r = \dfrac{3}{5} y

Thus; each disc is a circle with area

A = \pi ( \frac{3}{5} y)^2

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m = \rho_{water}A

= 62.4 × \pi ( \frac{3}{5} y)^2

= \dfrac{561.6}{25} \pi y^2

The distance pumped is 5-y

Thus; the workdone in pumping the tank by pumping the water over the top edge is :

W = \dfrac{561.6 \pi}{25} \int\limits^5_0 {(5-y)} \, y^2dy

W = \dfrac{561.6 \pi}{25} \int\limits^5_0 {(5y^2-y^3)} dy

W = \dfrac{561.6 \pi}{25}[52.083]

\mathbf{W = 1169.99 \pi \ ft-lbs}

The amount of workdone by in emptying the tank by pumping the water over the top edge is \mathbf{ 1169.99 \pi \ ft-lbs}

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4 years ago
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