Answer:
50%
Explanation:
Let's assume that the allele "T" gives the normal phenotype while the recessive allele "t" imparts the disease and is lethal in homozygous condition. The genotype of each of the two carrier parents would be "Tt". A cross between Tt and Tt would give the progeny in the following genotype ratio=
Tt x Tt= 1/4 TT: 1/2 Tt: 1/4 tt
Therefore, 1/2 or 50% progeny would be the carrier for the Tay-Sachs disease.
<span>Invasion of Privacy Damages and Recovery. ... This article will briefly describe some of the available remedies and consequences in invasion of privacy cases. Bear in mind that not all states recognize all four of the privacy torts, and even those that do differ with respect to the types of damages and recovery they award.</span>
Answer:
Eutrophication is an excess of
<u>plants</u><u> </u><u>and algal growth</u><u> </u>often caused by run-off from lawns or
farms that wash excess fertilizer into rivers or coastal waters.
plant.
Answer:
The correct answer is - the placenta, the site of exchange of materials between the mother and the fetus.
Explanation:
In the given diagram there is a representation of a human embryo developing in the uterus. Different parts are numbered and the number three represents the site of exchange of materials between the mother and the fetus and this organ is called the placenta. It is the organ that develops between fetus and uterus during pregnancy that allows substances such as nutrients, to diffuse from the mother's blood to the fetus and connected by the umbilical cord.
