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2 years ago

Help pleaseee, thank you.

Mathematics

1 answer:

Nookie1986 [14]2 years ago

4 0

Answer:9/40

Step-by-step explanation:

You’ll use the LCM which will be 40 so George 2/5 will be 16/40 and Tyler 3/8 will be 15/40 add those together and it’ll be 31/40 leaving Lance to do the last 9/40

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60 is 30% of what number?

Phantasy [73]

Percent means parts out of 100
30%=30/100=3/10

'of' means multiply

60 is 30% of what translates to
60=3/10 times what
multiply both sides by 10/3
600/3=what
200=what
the number is 200

7 0

3 years ago

Whats an approximate equation of a line that passes through the points (-4.3,2.3) and (1.3,-7.4)

Wewaii [24]

Use the 2 points to find the gradient of the line
Gradient = (y - y1)/(x - x1), y and y1 are the two different y values.
(2.3 - - 7.4)/(-4.3 - 1.3) = -97/56 = -1.732
Note: y and x both come from the same coordinate, and y1 and x1 also come from the same coordinates - (x , y), (x1 , y1)

Use the following to find the equation (x, x1, y, and y1 are not the same as the first part)
y - y1 = m(x - x1)

Where x2 and y2 is an intersection (one of the coordinates you used) and m is the gradient you found.
So...
y - 2.3 = -1.732(x - - 4.3)
You can simplify this if you are required to.

4 0

3 years ago

Please help, if you need more info to answer the question please lmk

katrin2010 [14]

I believe this is right but I’m not 100%

7 0

3 years ago

Urgent!!!! not worried about a but i need b and #4

Oksi-84 [34.3K]

b) The surface area is 564.5. Picture below.

4. Three possibilities.

Formula for volume of a cylinder: πr^2h

Formula for volume of sphere: 4/3πr^3

If the radius of the sphere is 1 inch than the volume is: 4.18879 or 4.19 rounded.

I used substitution on this website https://www.omnicalculator.com/math/volume

Just plug in the 4.18879 at the cylinder volume and put in a random number in the radius or height whichever you want then it'll give you the one you left blank. You'll find three possibilities for the radius and height of 4.18879 volume.

3 0

3 years ago

Use Lagrange multipliers to find the maximum and minimum values of (i) f(x,y)-81x^2+y^2 subject to the constraint 4x^2+y^2=9. (i

sp2606 [1]

i. The Lagrangian is

$L(x,y,\lambda)=81x^2+y^2+\lambda(4x^2+y^2-9)$

with critical points whenever

$L_x=162x+8\lambda x=0\implies2x(81+4\lambda)=0\implies x=0\text{ or }\lambda=-\dfrac{81}4$

$L_y=2y+2\lambda y=0\implies2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_\lambda=4x^2+y^2-9=0$

If $x=0$ , then $L_\lambda=0\implies y=\pm3$ .
If $y=0$ , then $L_\lambda=0\implies x=\pm\dfrac32$ .
Either value of $\lambda$ found above requires that either $x=0$ or $y=0$ , so we get the same critical points as in the previous two cases.

We have $f(0,-3)=9$ , $f(0,3)=9$ , $f\left(-\dfrac32,0\right)=\dfrac{729}4=182.25$ , and $f\left(\dfrac32,0\right)=\dfrac{729}4$ , so $f$ has a minimum value of 9 and a maximum value of 182.25.

ii. The Lagrangian is

$L(x,y,z,\lambda)=y^2-10z+\lambda(x^2+y^2+z^2-36)$

with critical points whenever

$L_x=2\lambda x=0\implies x=0$ (because we assume $\lambda\neq0$ )

$L_y=2y+2\lambda y=0\implies 2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_z=-10+2\lambda z=0\implies z=\dfrac5\lambda$

$L_\lambda=x^2+y^2+z^2-36=0$

If $x=y=0$ , then $L_\lambda=0\implies z=\pm6$ .
If $\lambda=-1$ , then $z=-5$ , and with $x=0$ we have $L_\lambda=0\implies y=\pm\sqrt{11}$ .

We have $f(0,0,-6)=60$ , $f(0,0,6)=-60$ , $f(0,-\sqrt{11},-5)=61$ , and $f(0,\sqrt{11},-5)=61$ . So $f$ has a maximum value of 61 and a minimum value of -60.

5 0

3 years ago