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lorasvet [3.4K]
2 years ago
11

The square pyramid represented below has a base edge of 6 inches and a height of 5 inches. What is the volume in cubic inches of

the pyramid
Mathematics
2 answers:
lawyer [7]2 years ago
8 0
6*6*5*(1/3)=60in cubed
vodomira [7]2 years ago
3 0
60 inches. cubed
explanation :
You might be interested in
-2y - 3y + 8 = 8 -5y - 12 <br><br> solve this equation fast please
Nina [5.8K]
I don’t think there’s a solution
8 0
2 years ago
Read 2 more answers
A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In
lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

                        P.Q. = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of males having blood disorder= \frac{250}{1000} = 0.25

\hat p_2 = sample proportion of females having blood disorder = \frac{275}{1000} = 0.275

n_1 = sample of males = 1000

n_2 = sample of females = 1000

p_1 = population proportion of males having blood disorder

p_2 = population proportion of females having blood disorder

<em>Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.</em>

<u>So, 95% confidence interval for the difference between the population proportions, </u><u>(</u>p_1-p_2<u>)</u><u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                             of significance are -1.96 & 1.96}  

P(-1.96 < \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < {(\hat p_1-\hat p_2)-(p_1-p_2)} < 1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

P( (\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < (p_1-p_2) < (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

<u>95% confidence interval for</u> (p_1-p_2) =

[(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }, (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }]

= [ (0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }, (0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} } ]

 = [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0
3 years ago
Middle school problem attached :D
suter [353]

Answer: $638.40

Step-by-step explanation:

45% converted to a decimal is 0.45

0.45 of $1200 = 0.45* $1200 (of in this case means multiply)

0.45 * $1200= $440

Because they said 11% of remaining salary, we have to do:

$1200-$440=$760

Now 11% converted to a decimal is 0.11

5% converted to a decimal is 0.05

So 0.11+0.05

0.11+0.05= 0.16

Now 0.16 *$760=$121.60

Now we find the remaining amount so we subtract: $760-$121.60= $638.40

So our answer is $638.40 left

7 0
1 year ago
Read 2 more answers
Please answer correctly
Scrat [10]
I think it’s 55.6 square inches

Sorry if I’m wrong! :)
5 0
2 years ago
How do you use a strategy of 30%of 900?
Julli [10]

Answer: 2 7 0

Step-by-step explanation:

1. We assume, that the number 900 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 900 is 100%, so we can write it down as 900=100%.

4. We know, that x is 30% of the output value, so we can write it down as x=30%.

5. Now we have two simple equations:

1) 900=100%

2) x=30%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

900/x=100%/30%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 30% of 900

900/x=100/30

(900/x)*x=(100/30)*x       - we multiply both sides of the equation by x

900=3.33333333333*x       - we divide both sides of the equation by (3.33333333333) to get x

900/3.33333333333=x

270=x

x=270

now we have:

30% of 900=270

3 0
3 years ago
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