The English alphabet contains 26 letters (a, b, c, ...y, z).
The digits from 0 to 9 are a total of 10.
A keycode contains 2 letters, and 3 numbers, for example:
AB 598; MM 139; NT 498; ...
So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of
26*26=676 possible pairs of letters.
Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :
10*10*10=1,000 possible triples of numbers.
Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of
676*1,000=676,000 keycodes.
Answer: 676,000
Answer:
Seth saved $90.
Step-by-step explanation:
1.Find out how much would be spent without buying the movie pass.
Multiply the amount of money that one would spend for each movie, by the number of movies one saw.
8 * 30 = 240
2.Find out the amount that was actually spent
Multiply the amount that was actually spent on each movie, by the number of movies that were seen. Then add the additional cost of the pass.
(4 * 30) + 30
= 120 + 30
= 150
3. Find the difference between the two values.
Subtract the amount that one was supposed to spend by the amount one did spend.
240 - 150
= 90
Answer:
Step-by-step explanation:
Answer:
-3
Step-by-step explanation:
Answer:
9. 
10. 
Step-by-step explanation:
9. Given the sequence
In this sequence,
Note that
then the common difference in this sequence is 
You have
then the explicit formula is
10. Given the sequence
In this sequence,
Note that
then the common difference in this sequence is 
You have
then the recursive formula is
