Ask question

Ask question

All categories

olya-2409 [2.1K]

2 years ago

14

Please help. will give brainliest

1 answer:

jenyasd209 [6]2 years ago

7 0

Answer:

C

Step-by-step explanation:

General probability is 3+5+4=12

3+4=7 (oranges and bananas answer is c

You might be interested in

Find the volume of a pyramid with a square base with a perimeter of the base is 5.7 cm in the height of the pyramid is 8.6

dexar [7]

Answer:

try 28.4 inches to the 3rd power

Step-by-step explanation:

4 0

3 years ago

What is the area of JHK

Anon25 [30]

Answer:

A (4.18

Step-by-step explanation:

You do 2.2 (base) x 3.8 (height) and divide it by 2

4 0

3 years ago

Multiplying polynomials (3m-1)(8m+7)

Zolol [24]

$(3m-1)(8m+7)=3m\cdot 8m+3m\cdot 7-1\cdot 8m-1\cdot 7=\\ \\=24m^2+21m-8m-7=24m^2+13m-7$

3 0

3 years ago

Read 2 more answers

The chair of the operations management department at Quality University wants to construct a p-chart for determining whether the

sasho [114]

Answer:

Prof B and Prof D

Step-by-step explanation:

Step-by-step explanation:

From the question we are told that

Sample size 100

Instructor Number of Failures

Prof. A 13

Prof. B 0

Prof. C 11

Prof. D 16

Confidence level= 0.95

From Z table

Z=1.96

Generally proportion for failure is mathematically given as

$Proportion\ of\ Failure\ P=\frac{Number\ of\ Failure\ N}{Sample\ size\ S}$

$P=\frac{N}{S}$

For Prof A

$P_A=\frac{N_A}{S}$

$P_A=\frac{13}{100}$

$P_A=0.13$

For Prof B

$P_B=\frac{N_B}{S}$

$P_B=\frac{0}{100}$

$P_B=0$

For Prof C

$P_C=\frac{N_C}{S}$

$P_C=\frac{11}{100}$

$P_C=0.11$

For Prof D

$P_D=\frac{N_D}{S}$

$P_D=\frac{16}{100}$

$P_D=0.16$

Generally the average proportional failure is mathematically given as

$P_a_v_g=\frac{0.13+0+0.11+0.16}{4}$

$P_a_v_g=0.10$

Therefore having this we calculate for the control limits

Generally the upper control limit UCl is mathematically given as

Upper control limits:

$UCL =P_a_v_g +Z\sqrt{\frac{P_a_v_g(1-P_a_v_g) }{S} }$

$UCL =0.1 +1.96\sqrt{\frac{0.1(1-0.1) }{100}}$

$UCL =0.1 +1.96*0.03$

$UCL =0.1 +0.0588$

$UCL =0.1588$

Generally the upper control limit UCl is mathematically given as

Lower limit control limits:

$UCL =P_a_v_g _Z\sqrt{\frac{P_a_v_g(1-P_a_v_g) }{S} }$

$UCL =0.1 -1.96\sqrt{\frac{0.1(1-0.1) }{100}}$

$UCL =0.1 -1.96*0.03$

$UCL =0.1 -0.0588$

$UCL =0.0412$

Therefore the Range is 0.0412 to 0.1588

Given the range 0.0412 to 0.1588 Prof B and Prof D are outside the Range making them the correct options

4 0

3 years ago

Which graph represents the function r(x) = |x – 2| - 1

maria [59]

Answer:you diddnt attach a graph but it woul have a stating pooint of positive 3 and a slove of up one over 1 so 1/1 +3

Step-by-step explanation:

5 0

3 years ago