Answer:
8% or 0.08
Step-by-step explanation:
Probability of missing the first pass = 40% = 0.40
Probability of missing the second pass = 20% = 0.20
We have to find the probability that he misses both the passes. Since the two passes are independent of each other, the probability that he misses two passes will be:
Probability of missing 1st pass x Probability of missing 2nd pass
i.e.
Probability of missing two passes in a row = 0.40 x 0.20 = 0.08 = 8%
Thus, there is 8% probability that he misses two passes in a row.
Answer:
<h2>1. subtract 3x, subtract 4, divide by -4</h2><h2 /><h2>2. add x</h2>
Step-by-step explanation:
1 + 3x = -x + 4.
subtract 3x
1 = -4x + 4
subtract 4
-3 = -4x
divide by -4
(-3)/(-4) = (4x)/(-4) ⇌ x = 3/4
-x + 6 = 5 - 3x
subtract 5
-x + 1 = - 3x
add x
1 = -2x
Answer:
6.28571428571
Step-by-step explanation:
Answer:
Step-by-step explanation:
Slope intercept form of a line is given by:
Where
m is the slope and b is the y-intercept
Given slope is 
We can write:
Now to find b, we replace x with -3 and y with -4, given, so we have:
So, the equation is:
Now,
The standard form is given by:
So, we take x and y to left side and the constant to right side. Rearranging, we get:
The first answer choice is right.
Answer:
4 consecutive goals
Step-by-step explanation:
If 3 of last 10 field goals = 30%
Which is equivalent to
(Number of goals scored / total games played) * 100%
(3 / 10) * 100% = 30%
Number of consecutive goals one has to score to raise field goal to 50% will be:
Let y = number of consecutive goals
[(3+y) / (10+y)] * 100% = 50%
[(3+y) / (10+y)] * 100/100 = 50/100
[(3+y) / (10+y)] * 1 = 0.5
(3+y) / (10+y) = 0.5
3+y = 0.5(10 + y)
3+y = 5 + 0.5y
y - 0.5y = 5 - 3
0.5y = 2
y = 2 / 0.5
y = 4
Therefore, number of consecutive goals needed to raise field goal to 50% = 4
