Answer:
Step-by-step explanation:
As you can see from the graph I attached you, the possible solutions in the interval from 0 to 2π are approximately:
So, it's useful to solve the equation too, in order to verify the result:
Taking the inverse sine of both sides:
Using this result we can conclude the solutions in the interval from 0 to 2π are approximately:
Answer:
It means that the whisker is shorter in the data
Step-by-step explanation:
Answer:
<h2>49</h2>
Step-by-step explanation:
Use PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
==============================================
(-5)² - 2 × (-9) + 6 <em>first </em><em>E</em><em>xponents</em>
25 - 2 × (-9) + 6 <em>next </em><em>M</em><em>ultiplication</em>
25 + 18 + 6 <em>next </em><em>A</em><em>ddition</em>
43 + 6 = 49
For domain 2x sqrt(2+x)>0
x>0,2+x>0,x>-2 combining
we get x>2
f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
Answer:
- 20
Step-by-step explanation:
Total Change in enrollment = - 60
Period of time at which change occurred = 3 years
Average change per year :
Total change in enrollment / period at which change occurred
= - 60 / 3
= - 20
Average change of - 20 enrollments per year
