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2 years ago

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Prove that 1=2 with well arranged steps and justify each step

1 answer:

Shtirlitz [24]2 years ago

3 0

<span>Justification Step 1: Let a = b. Step 2: Then a^2 = ab , Step 3: a^2 + a^2 = a^2 + ab , Step 4: 2a^2=a^2 + ab, Step 5: 2a^2 - 2ab = a^2 + ab - 2ab, Step 6: and 2a^2 - 2a^b = a^2 + ab - 2ab . Step 7: This can be written as 2(a^2 - ab) = 1(a^2 - ab) , Step 8: and cancelling the (a^2 - ab) from both sides gives 1 = 2.</span>

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Solve the system by elimination.(show your work)

PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

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2 years ago

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A mother invests $7000 in a bank account at the time of her daughter's birth. The interest is 18) compounded quarterly at a rate

Alex

well, from birth to your twentieth birthday that'll just be 20 years, so

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2 years ago

If a triangle is an equilateral triangle, then the triangle has exactly three 60°

ahrayia [7]

Step-by-step explanation:

In an equilateral triangle, all the three sides are equal as well as all the angles are equal. Let the angles be x.

We know that the sum of angles of a triangle is equal to 180 degrees. It means that,

x+x+x=180

3x=180

x=60°

Hence, if a triangle is an equilateral triangle, then the triangle has exactly three 60° angles. Hence, △ABC is an equilateral triangle

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

The ratio of girls to boys in 6th grade is 3:4. If there are 182 6th graders, how many are girls

nataly862011 [7]

Answer:

78 girls

Step-by-step explanation:

Ratio is 3:4, so that means the total number of 182 can be divided into 7 parts. 182 divided by 7 is 26, so each part is 26. The ratio of girls is 3, so 3 times 26 is 78. You can check this by putting (3*26)/(4*26) simplifies to 78/104 to 3/4 which is the right ratio

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3 years ago

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