Prove that 1=2 with well arranged steps and justify each step

1 answer:

3 0

<span>Justification Step 1: Let a = b. Step 2: Then a^2 = ab , Step 3: a^2 + a^2 = a^2 + ab , Step 4: 2a^2=a^2 + ab, Step 5: 2a^2 - 2ab = a^2 + ab - 2ab, Step 6: and 2a^2 - 2a^b = a^2 + ab - 2ab . Step 7: This can be written as 2(a^2 - ab) = 1(a^2 - ab) , Step 8: and cancelling the (a^2 - ab) from both sides gives 1 = 2.</span>

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PLEASE HELP! I HAVE A TIME LIMIT AND IM BEHIND

Kipish [7]

Answer:

Part A none

Part B drawn

Step-by-step explanation:

Suppose the transversal intersects a pair of parallel lines it creates two pairs of alternate exterior angles.

Now if we look at the first figure we find that the alternate exterior angle 1 and 4 are equal . Also 3 and 2 are equal.

But <1 and < 2 are not equal . They are supplementary angles. Their sum is equal to 180 degrees.

Similarly angles 3 and4 are supplementary angles.

This situation does not support Ricky's claim. So you will select none in part A.

Now in part B we see that angle 5 &8 are equal and 6 & 7 are congruent.

This refutes Ricky's claims and this can be proved mathematically.

Angles 5 & 6 are supplementary angles. Similarly 7 & 8 are supplementary therefore they cannot be equal as they are unequal and a transversal is drawn not a perpendicular.