First of all, recall the definition of absolute value:
So if <em>x</em> < 4, then <em>x</em> - 4 < 0, so |<em>x</em> - 4| = -(<em>x</em> - 4), and the first case in <em>h(x)</em> reduces to
Next, in order for <em>h(x)</em> to be continuous at <em>x</em> = 4, the limits from either side of <em>x</em> = 4 must be equal and have the same value as <em>h(x)</em> at <em>x</em> = 4. From the given definition of <em>h(x)</em>, we have
Compute the one-sided limits:
• From the left:
• From the right:
If the limits are to be equal, then
-1 = 5<em>k</em> - 16
Solve for <em>k</em> :
-1 = 5<em>k</em> - 16
15 = 5<em>k</em>
<em>k</em> = 3
Answer:
Step-by-step explanation:
<u>Second-Degree Equation</u>
The second-degree equation or quadratic equation has the general form
where a is non-zero.
There are many methods to solve the equation, one of the most-used is by using the solver formula:
The equation of the question has the values: a=1, b=2, c=4, thus the values of x are
Since the square root has a negative argument, both solutions for x are imaginary or complex. Simplifying the radical
The solutions are
Answer:
I' would say A but C could be a possibility.
Step-by-step explanation:
To move it up 4 you would add 4 at the end of the equation
the tricky part is to get it shifted 1 place to the left
do do this you need to add 1 to X before raising it to the 3rd power
so F(x) is (x+1)^3 +4
Answer:
Disagree
Step-by-step explanation:
X+y equals 9 if 4 replaces x and 5 replaces y not 10.
