Answer:
12.6 L CO2
Explanation:
Mass = 24.7 grams
Molar mass = 44.01 g/mole
Volume at STP = ?
The relationship between these quantities is given as
Number of moles = Mass / Molar mass
Number of moles = 24.7 g / 44.01 g/mole
Number of moles = 0.5612 moles
1 mol = 22.4 L
0.5612 mol = x
x = 0.5612 * 22.4
x = 12.6 L
This is a combustion reaction so there is a hydrocarbon + oxygen which always gives you carbon dioxide and water.
So: C4H10+O2-->CO2+H2O
The balanced equation would be:
2C4H10+13O2-->8CO2+10H2O <- so that's the molecular formula for butane.
Is there a picture of the isotope or?- becaue I can’t help if I don’t have a visual.
Answer: The vapor pressure of Fe at
is 465 mm Hg
Explanation:
The vapor pressure is determined by Clausius Clapeyron equation:
![ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})](https://tex.z-dn.net/?f=ln%28%5Cfrac%7BP_2%7D%7BP_1%7D%29%3D%5Cfrac%7B%5CDelta%20H_%7Bvap%7D%7D%7BR%7D%28%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%29)
where,
= initial pressure at
= 400 mm Hg
= final pressure at
= ?
= enthalpy of vaporisation = 351 kJ/mol = 351000 J/mol
R = gas constant = 8.314 J/mole.K
= initial temperature = 2890 K
= final temperature = 2920 K
Now put all the given values in this formula, we get
![\log (\frac{P_2}{400})=\frac{351000}{2.303\times 8.314J/mole.K}[[\frac{1}{2890K}-\frac{1}{2920K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BP_2%7D%7B400%7D%29%3D%5Cfrac%7B351000%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5B%5Cfrac%7B1%7D%7B2890K%7D-%5Cfrac%7B1%7D%7B2920K%7D%5D)
![\log (\frac{P_2}{400})=0.06517](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BP_2%7D%7B400%7D%29%3D0.06517)
![(\frac{P_2}{400})=1.162](https://tex.z-dn.net/?f=%28%5Cfrac%7BP_2%7D%7B400%7D%29%3D1.162)
![P_2=465mmHg](https://tex.z-dn.net/?f=P_2%3D465mmHg)
Thus the vapor pressure of Fe at
is 465 mm Hg
Answer:
Answer in explanation
Explanation:
a. Boron , element 5
Helium has 2 electrons, add to the other 3 to give 5.
Other group members are : Aluminum Al, Gallium Ga, Indium In , Thallium Tl and Nihonium Nh
b. Sulphur, element 16
Neon is 10 , add other 6 electrons to make 16
Other group members are: Oxygen O, selenium Se , Tellurium Te and Polonium Po
c. Lanthanum, element 57
Xenon is 54, add the other 3 electrons to give 57.
Other elements in group : Scandium Sc , Yttrium Y , Actinium Ac, Lutetium Lu and/or Lawrencium Lr