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Bond [772]
3 years ago
14

F1

Chemistry
1 answer:
ololo11 [35]3 years ago
7 0

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of Atomic Structure.

Since, We all know that, To draw any Electron-Dot Structure, we always have to know the exact Number of valence or free electrons of any atom or molecule, hence

The Correct Answer is :-

D. Number of valence electrons.

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15. If the moon is 384,400km away. Does it take more than a second for light to travel from the Earth to the moon?​
marishachu [46]

Answer:

Yes

Explanation:

The speed of light is about 300 000 km per second, so light takes about 1.28 seconds to travel from the Moon to the Earth.

3 0
1 year ago
25 L of a gas is collected at 115 kPa. If the pressure increases to 300 kPa, what is the new volume?
Lina20 [59]

Answer:

V2 = 9.58 Litres.

Explanation:

Given the following data;

Initial volume = 25 L

Initial pressure = 115 kPa

Final pressure = 300 kPa

To find the new volume V2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

PV = K

P_{1}V_{1} = P_{2}V_{2}

Substituting into the equation, we have;

115 * 25 = 300*V_{2}

2875 = 300*V_{2}

V_{2} = \frac {2875}{300}

V_{2} = 9.58

V2 = 9.58 L

Therefore, the new volume is 9.58 litres.

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2 years ago
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2 years ago
Determine the value of the equilibrium constant, Kgoal, for the reactionN2(g)+H2O(g)⇌NO(g)+12N2H4(g), Kgoal=?by making use of th
Black_prince [1.1K]

Answer:

K_{goal}=1.793*10^{-33}

Explanation:

N2(g)+O2(g)⇌2NO(g), K_1 = 4.10*10^{-31}

N2(g)+2H2(g)⇌N2H4(g), K_2 = 7.40*10^{-26}

2H2O(g)⇌2H2(g)+O2(g), K_3 = 1.06*10^{-10}

If we add above reaction we will get:

2N2(g)+2H2O(g)⇌2NO(g)+N2H4(g)                     Eq (1)

Equilibrium constant for Eq (1) is K_1*K_3*K_3

Divide Eq (1) by 2, it will become:

N2(g)+H2O(g)⇌NO(g)+1/2N2H4(g)                       Eq (2)  

Equilibrium constant for Eq (2) is (K_1*K_3*K_3)^{1/2}

Equilibrium constant =K_{goal}= (K_1*K_2*K_3)^{1/2}\\K_{goal}= (4.10*10^{-31} *7.40*10^{-26}*1.06*10^{-10})^{1/2}\\K_{goal}=1.793*10^{-33}

7 0
3 years ago
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