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3 years ago

How many moles are in 48 grams of Chlorine? ( hint remember some elements are diatomic)

Chemistry

1 answer:

marusya05 [52]3 years ago

3 0

Answer:

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Explanation:

srry preicsoe pntosod

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Which of the following statements are true about metallic bonds?

Alborosie

Answer:

B. They bond identical atoms together

Explanation:

Metallic Bond: This is the bond that exists among the atoms of the metal. This is a type of electrostatic attraction between conduction electrons of metallic atom and their positively charged metal ions.

(figure attached)

Example:

Copper is a metallic element and its atoms consist of metallic bond among their selves.

Options A, B, D are not correct as all states for a kind of ionic bond formation.

Ionic bond:

It form by the complete transfer of electron from one atom to other

It is formed among two atoms of different electronegativities.

Also metals are electro-positive and non -metals are electro-negative so they form ionic bond.

Example is NaCl where sodium is a metal and Chloride is non-metal and they from ionic bond.

7 0

3 years ago

PLEASE HELP!!!!!!!

butalik [34]

1. yes

2. chemicals

3. 29

4. 1.6

8 0

3 years ago

Calculate ΔHrxn for the following reaction: C(s) + H2O(g) --> CO(g) + H2(g) Use the following reactions and given ΔH values:

valentina_108 [34]

Answer:

ΔH = 130.5 kJ

Explanation:

Hello,

In this case, by using the Hess law, we compute the enthalpy of the required reaction:

C(s) + H2O(g) --> CO(g) + H2(g)

Thus, the first step is to keep the following reaction unchanged:

C (s) + O2 (g) → CO2 (g), ΔH = -393.5 kJ

Next, we invert and halve this reaction:

2 CO (g) + O2 (g) → 2 CO2 (g), ΔH= -566.0 kJ

So the enthalpy of reaction is inverted and halved:

CO2 (g) → CO (g) + 1/2 O2 (g) ΔH= 283 kJ

Then, we also invert and halve this reaction:

2 H2 (g) + O2 (g) → 2 H2O ΔH= -483.6 kJ

So the enthalpy of reaction is inverted and halved as well:

H2O → H2 (g) + 1/2 O2 (g) ΔH= 241.8 kJ

Finally, we add the three reactions to obtain the required reaction:

= C (s) + O2 (g) + CO2 (g) + H2O → H2 (g) + 1/2 O2 (g) + CO (g) + 1/2 O2 (g) + CO2 (g)

= C (s) + O2 (g) + CO2 (g) + H2O → H2 (g) + O2 (g) + CO (g) + CO2 (g)

= C (s) + H2O → H2 (g) CO (g)

So enthalpy is computed by:

ΔH = -393.5 kJ + 283 kJ + 241.8 kJ

ΔH = 130.5 kJ

Best regards.

5 0

3 years ago

Help plz:))) I’ll mark u brainliest

tatuchka [14]

The correct answer is

B.The elements all have three valence electrons

8 0

3 years ago

Read 2 more answers

How many significant figures does 2.0 x 10² have?

Masteriza [31]

Answer:

Two sig figs

Explanation:

Non-zero integers always count as sig figs (the 2 before the decimal point), and any trailing zeros at the right end of the number are significant only if there is a decimal point (in this case, the 0 is significant). Therefore, there are 2 sig figs in 2.0 x $10^{2}$

6 0

3 years ago