Answer:
monochlorinated products: 4
dichlorinated products: 12
Explanation:
Chlorination of alkanes is a reaction that takes place when the chlorine is in presence of light. This actually decomposes the chlorine, and one atom of Chlorine substracts an hydrogen from the alkane. Now, this hydrogen substracted comes usually from the most substitued carbon, because it's more stable (A tertiary carbon is more stable than a secondary carbon, and this more stable than primary).
When this happens, the other chlorine atom, goes as electrophyle in that carbon and formed the chlorinated product. Now, although a tertiary carbon is more stable, we can still have (in minor quantities) chlorinated products that comes from a secondary and primary carbon. The first picture shows the general mechanism of the chlorination, and the possible products for a monochlorinated.
The second picture shows the possible dichlorinated products, which are in higher quantities than the monochlorinated basicallu because of the variety of positions the chlorine can be. So, second picture shows all the products.
Answer:
Sodium
Explanation:
Its neighbor to the bottom (sodium) has similar properties to lithium. Group trends are very strong for the Group 1 (alkali) and Group 2 (alkaline earths) metals. Group 1 elements behave very similarly to each other.
Answer:
Energy of motion is called
The masses of the 2 most
common isotopes of Cl are 35 and 37. Therefore we can formulate 3 possible
masses of Cl2:
<span>
35 + 35 = 70
35 + 37 = 72
37 + 37 = 74
<span>However, Cl 35 is the most common isotope of chlorine of the
two therefore it is the most probable that two Cl 35 atoms will combine, so 70
is the most common among all.
</span></span>
Answer:- 47.62 mL
Solution:- It is a dilution problem where we are asked to calculate the volume of 15.75 M perchloric acid solution required to make 500.0 mL of 1.500 M solution.
For solving this type of problems we use the dilution equation:
Where, 
is the concentration of the concentrated solution and 
is it's volume.
is the concentration of the diluted solution and 
is it's volume. Let's plug in the values in the equation and solve it for .
On rearranging this for :
So, 47.62 mL of 15.75 M perchloric acid are required to make 500.0mL of 1.500 M solution.
