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2 years ago

The type of measurement that involves observing and describing the events of an experiment is called:

Chemistry

1 answer:

N76 [4]2 years ago

3 0

Answer:

Data collection/ analysis

I think. Its part of the scientific method

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The veterinarian prescribes the NSAID carprofen for a 50-pound dog with arthritis at a dose of 4.4 mg/kg and would like this dos

alina1380 [7]

Answer:

The dog should be given half of 100 mg tablet in the morning and another half of 100 mg tablet in an evening.

Explanation:

Weight of the dog = 50 pounds = 22.68 kg

1 kg = 2.205 pounds

Amount of daily dose prescribed by doctor = 4.4 mg/kg

Total mount of dose = 4.4 mg/kg × 22.68 kg = 99.79 mg

99.79 mg ≈ 100 mg

49.89 mg ≈ 50 mg

So, according to doctor prescription dog should be given half 100 mg tablet in the morning and another half of 100 mg tablet in an evening.

8 0

3 years ago

Which list was easier to sort

drek231 [11]

The answer is "List 2". They're all in scientific notation, so it's easier to organize than List 1, which is in both normal notation and scientific notation.

7 0

3 years ago

What is a Newton? explain please

Lina20 [59]

Answer:

it is the unit of Force

Explanation:

force is equal to Newton

5 0

2 years ago

Read 2 more answers

Approximately how many elements are there that combine chemically in a great number of ways to produce compounds? A. 25 B. 50 C

Arturiano [62]

100 as there’s approximately 100 discovered elements

8 0

3 years ago

Read 2 more answers

Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili

Katen [24]

Answer: The value of equilibrium constant for the given reaction is 56.61

Explanation:

We are given:

Initial moles of iodine gas = 0.100 moles

Initial moles of hydrogen gas = 0.100 moles

Volume of container = 1.00 L

Molarity of the solution is calculated by the equation:

$\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}$

$\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M$

$\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M$

Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

$H_2+I_2\rightleftharpoons 2HI$

Initial: 0.1 0.1

At eqllm: 0.1-x 0.1-x 2x

Evaluating the value of 'x'

$\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[HI]^2}{[H_2][I_2]}$

$[HI]_{eq}=2x=(2\times 0.079)=0.158M$

$[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M$

$[I_2]_{eq}=0.0210M$

Putting values in above expression, we get:

$K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61$

Hence, the value of equilibrium constant for the given reaction is 56.61

6 0

3 years ago