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3 years ago

8

Sonya makes a pattern of values for X in a pattern of values for Y which ordered pair continues the pattern and has an x- value

of 6

1 answer:

MA_775_DIABLO [31]3 years ago

8 0

This is for points sorry

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balu736 [363]

I don’t know sorry please somebody else can help you

8 0

2 years ago

Helpp please show work!

atroni [7]

Answer:

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7 0

3 years ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>

To find - <u>Area </u><u>of </u><u>trapezium</u>

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

<u>Construction</u><u> </u><u>-</u>

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

2 years ago

A cylinder has a height of 18 millimeters and a radius of 18 millimeters. What is its volume? Use ≈ 3.14 and round your answer

solong [7]

Answer:

$Volume = 18312.48$

Step-by-step explanation:

Given

$Height (h) = 18mm$

$Radius (r) = 18mm$

Required

Determine the volume

The volume of a cylinder is calculated as thus:

$Volume = \pi r^2h$

Substitute values for r and h

$Volume = 3.14 * 18^2 * 18$

$Volume = 18312.48$

<em>Hence, the volume of the cylinder is 18312.48mm³</em>

8 0

3 years ago

Clara is building a triangular garden. She wants the length of the longest side to be three more than twice as long as the lengt

zheka24 [161]

The garden's perimeter = 3+2s+12+s.

The simpler version of the expression = 15+3s.

The variable's frequency in the abbreviated statement is 3.

<h3>Calculation of a triangle's perimeter:</h3>

The triangle's perimeter is equivalent to the sum of its edges, where a, b, and c are its sides.

Let the triangle's longest edge be 'a'
shorter one to be 's'
the opposite side 'b'

With the information provided, the formula will become 'a = 3+2s'

and 'b' is also 12 ft.

Triangle perimeter =the total of its edges

= a + b + s

= 3 + 2s + 12 + s

= 15 + 3s

As a result, the garden's perimeter = 3+2s+12+s.

Therefore,the simpler version of the formula is 15+3s.

The variable's coefficient in the abbreviated statement is 3.

Learn more about triangle perimeter:

brainly.com/question/23935199?referrer=searchResults

#SPJ10

7 0

2 years ago