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enyata [817]
3 years ago
15

What kinds of things can we learn by studying atoms?​

Chemistry
1 answer:
katovenus [111]3 years ago
5 0

Answer:

how and why things react, like why something turns into a gas or why something explodes.

Explanation:

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Because in SI, the expectation is that area and volume will be expressed in terms of a linear dimension( the metre) or its multiples.
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How many atoms are in 4.93 moles hcl?
trasher [3.6K]
1 mole ------------- 6.02x10²³ atoms
4.93 moles ------- ??

4.93 x ( 6.02x10²³) / 1 = 

=> 2.96x10²⁴ atoms
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How can we tell when something is polar or non-polar in an Inter-molecular Force?
Montano1993 [528]
If the substance mixes with water it's polar. If it doesn't it ms non polar.
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3 years ago
Calculate the ph of a dilute solution that contains a molar ratio of potassium acetate to acetic acid (pka ???? 4.76) of (a) 2:1
givi [52]

According to Hasselbach-Henderson equation:

pH=pK_{a}+log\frac{[A^{-}]}{[HA]}

Here, [A^{-}] is concentration of conjugate base and [HA] is concentration of acid.

In the given problem, conjugate base is CH_{3}COOK and acid is CH_{3}COOH thus, Hasselbach-Henderson equation will be as follows:

pH=pK_{a}+log\frac{[CH_{3}COOK]}{[CH_{3}COOH]}...... (1)

(a) Ratio of concentration of potassium acetate and acetic acid is 2:1 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=2

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{2}{1}=5.06

Therefore, pH of solution is 5.06.

(b) Ratio of concentration of potassium acetate and acetic acid is 1:3 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{3}

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{1}{3}=4.28

Therefore, pH of solution is 4.28.

(c)Ratio of concentration of potassium acetate and acetic acid is 5:1 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{5}{1}

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{5}{1}=5.45

Therefore, pH of solution is 5.45.

(d) Ratio of concentration of potassium acetate and acetic acid is 1:1 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=1

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{1}{1}=4.76

Therefore, pH of solution is 4.76.

(e) Ratio of concentration of potassium acetate and acetic acid is 1:10 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{10}

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{1}{10}=3.76

Therefore, pH of solution is 3.76.

4 0
3 years ago
Balance the following equation<br>Al + O₂ - ALO₃​
baherus [9]

Answer:

2Al + 3O₂ ===> 2ALO₃

Explanation:

2Al + 3O₂ ===> 2ALO₃

6 0
3 years ago
Read 2 more answers
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