1) Has zeros at -2 and 4, both being double roots 2) As x→∞, y→−∞

1 answer:

3 0

-(x+2)^2(x-4)^2

Not that if x= -2 and x=4 they will look like this in an equation: (x+2) and (x-4)
When (x+2) and (x-4) are set equal to zero and you solve for x, x will equal x= -2 and x=4

If they have double roots, they have a multiplicity of 2 (per root) meaning they will bounce off of the x-axis. Multiplicity can be found by using exponents.

The negative in front flips the function over the x-axis and holds true to the given limit.

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Given \tan A = \frac{7}{{24}}, find the cos B

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we know that

$tan(A)=\frac{opposite}{adjacent}$

so, we get

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now, we can find hypotenuse

$hypotenuse=\sqrt{7^2+24^2}$

$hypotenuse=25$

now, we can draw triangle and then switch vertices accordingly

we can find cos(B) using second triangle

$cos(B)=\frac{adjacent}{hypotenuse}$

In second triangle:

adjacent=7

hypotenuse =25

so, we get

$cos(B)=\frac{7}{25}$ ................Answer

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