<u>Answer:</u> The molarity of NaOH solution is 0.273 M.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
Given mass of KHP = 1.794 g
Molar mass of KHP = 204.2 g/mol
Putting values in above equation, we get:
![\text{Moles of KHP}=\frac{1.794g}{204.2g/mol}=0.0088mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20KHP%7D%3D%5Cfrac%7B1.794g%7D%7B204.2g%2Fmol%7D%3D0.0088mol)
The chemical reaction for the reaction of KHP and NaOH follows
![KHC_8H_4O_4(aq.)+NaOH\rightarrow KNaC_8H_4O_4(aq.)+H_2O(l)](https://tex.z-dn.net/?f=KHC_8H_4O_4%28aq.%29%2BNaOH%5Crightarrow%20KNaC_8H_4O_4%28aq.%29%2BH_2O%28l%29)
By Stoichiometry of the reaction:
1 mole of KHP reacts with 1 mole of NaOH.
So, 0.0088 moles of KHP will react with =
of NaOH
To calculate the molarity of NaOH, we use the equation:
![\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}](https://tex.z-dn.net/?f=%5Ctext%7BMolarity%20of%20the%20solution%7D%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20solute%7D%7D%7B%5Ctext%7BVolume%20of%20solution%20%28in%20L%29%7D%7D)
We are given:
Moles of NaOH = 0.0088 moles
Volume of solution = [32.47 - 0.23] mL = 32.24 mL = 0.03224 L (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
![\text{Molarity of NaOH }=\frac{0.0088mol}{0.03224L}=0.273M](https://tex.z-dn.net/?f=%5Ctext%7BMolarity%20of%20NaOH%20%7D%3D%5Cfrac%7B0.0088mol%7D%7B0.03224L%7D%3D0.273M)
Hence, the molarity of NaOH solution is 0.273 M.