Answer:
I believe the organelle should replace the question mark!
Hello!
First, HNO₃ dissociates in the following way:
HNO₃(aq) → H⁺(aq) + NO₃⁻(aq)
Next, there is a neutralization reaction with Methylamine:
H⁺(aq) + CH₃NH₂(aq) → CH₃NH₃⁺(aq)
Finally, the formed methylammonium ion weakly dissociates in the following way:
CH₃NH₃⁺(aq) + H₂O(l) ⇄ H₃O⁺(aq) + CH₃NH₂ (aq)
From this sequence of reactions, we can see that the resulting solution would be slightly more acidic than the initial one, as the buffer solution resists the addition of strong acid.
Have a nice day!
Answer : The volume in mL of the sodium carbonate stock solution is 364 mL.
Explanation :
According to dilution law:
where,
= molarity of aqueous sodium carbonate
= molarity of aqueous sodium carbonate stock solution
= volume of aqueous sodium carbonate
= volume of aqueous sodium carbonate stock solution
Given:
= 1.00 M
= 1.58 M
= 575 mL
= ?
Now put all the given values in the above formula, we get:
Therefore, the volume in mL of the sodium carbonate stock solution is 364 mL.
