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3 years ago

Gravity is needed to determine an object's _____.

Chemistry

2 answers:

Lana71 [14]3 years ago

6 0

Weight is affected by gravitational force

Afina-wow [57]3 years ago

5 0

Weight it’s needed to determine and objects weight

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A 33.153 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis ap

elena-14-01-66 [18.8K]

Answer:

The empirical formula of the compound = $C_4H_8S_1O_1$

Explanation:

Mass of carbon dioxide gas = 59.060 mg = 0.059060 g

1 mg = 0.001 g

Moles of carbon dioxide = $\frac{0.059060 g}{44 g/mol}=0.0013 mol$

Moles of carbon in 0.0013 moles of carbon dioxide gas = 1 × 0.0013 mol = 0.0013 mol

Mass of 0.0013 moles of carbon = $12 g/mol\times 0.0013 mol=0.0156 g$

Mass of water = 24.176 mg = 0.024176

Moles of water = $\frac{0.024176 g}{18 g/mol}=0.0013 mol$

Moles of hydrogen in 0.0013 moles of water = 2 × 0.0013 mol = 0.0026 mol

Mass of 0.0013 moles of hydrogen= $1 g/mol\times 0.0013 mol=0.0013 g$

Mass of sulfur dioxide = 20.326 mg = 0.020326 g

Moles of sulfur dioxide = $\frac{0.020326 g}{64 g/mol}=0.00032 mol$

Moles of sulfur in 0.00032 moles of sulfur dioxide = 1 × 0.00032 mol = 0.00032 mol

Mass of 0.00032 moles of sulfur = $32 g/mol\times 0.00032 mol=0.01024 g$

Mass of oxygen in the sample = x

Mass of sample = 33.153 mg = 0.033153 g

0.033153 g = 0.0156 g + 0.0013 g + 0.01024 g + x

x = 0.006013 g

Moles of oxygen = $\frac{0.006013 g}{16 g/mol}=0.00038 mol$

For empirical formula divide the lowest number of moles of elemnt from all the moles of the all the elements:

Carbon : $\frac{0.0013 mol}{0.00032 mol}=4$

Hydrogen: $\frac{0.0026 mol}{0.00032 mol}=8$

Sulfur : $\frac{0.00032 mol}{0.00032 mol}=1$

Oxygen : $\frac{0.00038 mol}{0.00032 mol}=1$

The empirical formula of the compound = $C_4H_8S_1O_1$

8 0

4 years ago

Elements in the same column down belong to the same.......

vladimir2022 [97]

I think the answer is the number of electrons. Hope it help :)

8 0

4 years ago

As a part of a clinical study, a pharmacist is asked to prepare a modification of a standard 22g package of a 2% mupirocin ointm

Vesna [10]

Answer:

226.8 mg of mupirocin powder are required

Explanation:

Given that;

weight of standard pack = 22 g

mupirocin by weight = 2%

so weight of mupirocin = 2% × 22 = 2/100 × 22 = 0.44 g

so by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment

mg of mupirocin powder are required = ?, lets rep this with x

Total weight of ointment = 22 + x g

Amount of mupirocin = 0.44 + x g

percentage of mupirocin in ointment is 3?

3/100 = 0.44 + x g / 22 + x g

3( 22 + x g ) = 100( 0.44 + x g )

66 + 3x g = 44 + 100x g

66 - 44 = 100x g - 3x g

97 x g = 22

x g = 22 / 97

x g = 0.2268 g

we know that; 1 gram = 1000 Milligram

so 0.2268 g = x mg

x mg = 0.2268 × 1000

x mg = 226.8 mg

Therefore, 226.8 mg of mupirocin powder are required

8 0

3 years ago

Isopentyl acetate is the molecule largely responsible for the aroma and taste of bananas. It is made up of carbon, hydrogen, and

k0ka [10]

Answer:

Explanation:

7.706 g of CO₂ will contain 12 x 7.706 / 44 g of C

= 2.1 g of C .

This will be contained in 3.256 g of isopentyl acetate

3.156 g of H₂O will contain 2 x 3.156 / 18 g of H

= .351 g of H

This will be contained in 3.256 g of isopentyl acetate

Rest will be oxygen

amount of oxygen in 3.256 g of isopentyl acetate

= 3.256 - ( 2.1 + .351 )

= .805 g

ratio of C , H , O in isopentyl acetate

= 2.1 g : .351 g : .805 g

2.1 / 12 : .351 / 1 : 0.805 / 16 ratio of moles

= .175 : .351 : .05 ratio of moles

= 3.5 : 7.02: 1

= 7 : 14 : 2

empirical formula of isopentyl acetate

= C₇ H₁₄ O₂ .

5 0

3 years ago

The ratio of chlorine to hydrogen chloride in the reaction H2(g) + Cl2 (g) -> 2 HCl(g) is

cupoosta [38]

It is a simple stoichiometry problem. We have been given with balanced equation and 5.00 moles of HCl and have to calculate the moles of H2.

From the balanced equation it is being clear that 2 moles of HCl are produced by 1 mole of H2. so, 1 mole of HCl will be produced by 1/2 moles of H2. So, the mole ratio of H2 and HCl is 1:2 
to calculate the moles of H2 for the given moles of HCl, multiply the moles of HCl by the mole ratio of H2 and HCl. 

5.00 mole HCl x (1 mole H2/ 2 mole HCl) 
= 2.50 mole H2 
so, to produce 5.00 moles of HCl, 2.50 moles of H2 are required.

8 0

3 years ago