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Sergio [31]
2 years ago
7

Which equation has the same solution as x2 - 6x – 14 = 0?how i do this​

Mathematics
1 answer:
Stells [14]2 years ago
5 0

Answer: 1.79

Step-by-step explanation: x2−6x−14=0

For this equation: a=1, b=-6, c=-14

1x2+−6x+−14=0

Step 1: Use quadratic formula with a=1, b=-6, c=-14.

x=

−b±√b2−4ac

2a

x=

−(−6)±√(−6)2−4(1)(−14)

2(1)

x=

6±√92

2

x=3+√23 or x=3−√23

Answer:

x=3+√23 or x=3−√23= 1.79

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Galina runs a bakery, where she sells packages of 4 dozen cookies for $24.96 per package. The amount of money she makes by selli
elena-s [515]

Answer:

p(x) = f(x) - g(x) = -0.04x² + 20.96x - 71

Explanation:

The sales are given by f(x) = 24.96x and the cost are represented by g(x) = 0.04x² + 4x + 71.

Then, the profit is equal to

p(x) = f(x) - g(x)

p(x) = 24.96x - (0.04x² + 4x + 71)

p(x) = 24.96x - 0.04x² - 4x - 71

p(x) = -0.04x² + 20.96x - 71

Therefore, the answer is

p(x) = f(x) - g(x) = -0.04x² + 20.96x - 71

4 0
1 year ago
1. Sheena and her friends want to form a team to play recreational soccer. They want a combination of males and females for the
Vikki [24]
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8 0
3 years ago
Please help me i have no clue what the answer is :?
Nadusha1986 [10]

Answer:

1. Yes

2. They could change the 60° angle into a different one.

Step-by-step explanation:

1. Two triangles are the same if they share two side lengths with the same angle between them.

2. Since the triangles are equal if they share two side lengths with the same angle between them, if they changed the angle between 3 and 5, it'd no longer be the same triangle.

5 0
3 years ago
Read 2 more answers
F(x)= x squared -3x + 2 divided by 3x squared + 9 x -12
VashaNatasha [74]

Answer:

=(x-2)/3(x+4)

Step-by-step explanation:

F(x)=x²-3x+2/3x²+9x-12

Using mid term break formula

=x²-2x-x+2/3(x²+3x-4)

=x(x-2)-1(x-2)/3(x²+4x-x-4)

=(x-2)(x-1)/3{x(x+4)-1(x+4)}

=(x-2)(x-1)/3(x-1)(x+4)

Cancelling (x-1)

We get

=(x-2)/3(x+4)

Hope it helps :)

6 0
3 years ago
PLEASEEE HURRYYY
Masteriza [31]

Answer:

(2,-5) and (2,1).

Step-by-step explanation:

We need to find the find all the points having an x coordinate of 2 whose distance from the point (-2,-4) is 5.

A circle with center (-2,-4) and radius 5 represents all the points whose distance from the point (-2,-4) is 5.

Standard form of a circle is

(x-h)^2+(y-k)^2=r^2

where, (h,k) is center and r is the radius.

(x-(-2))^2+(y-(-4))^2=(5)^2

(x+2)^2+(y+2)^2=25

Now, put x=2.

(2+2)^2+(y+2)^2=25

(4)^2+(y+2)^2=25

(y+2)^2=25-16

(y+2)^2=9

Taking square root on both sides.

y+2=\pm\sqrt{9}

y+2=\pm3

y+2=-3\text{ or }y+2=3

y=-5\text{ or }y=1

So, the y-coordinates of the points are -5 and 1.

Therefore, the required points are (2,-5) and (2,1).

8 0
3 years ago
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