<h3>Given</h3>
Two positive numbers x and y such that xy = 192
<h3>Find</h3>
The values that minimize x + 3y
<h3>Solution</h3>
y = 192/x . . . . . solve for y
f(x) = x + 3y
f(x) = x + 3(192/x) . . . . . the function we want to minimize
We can find the x that minimizes of f(x) by setting the derivative of f(x) to zero.
... f'(x) = 1 - 576/x² = 0
... 576 = x² . . . . . . . . . . . . multiply by x², add 576
... √576 = x = 24 . . . . . . . take the square root
... y = 192/24 = 8 . . . . . . . find the value of y using the above equation for y
The first number is 24.
The second number is 8.
Answer:
Area of the rhombus will be a repeating decimal.
Step-by-step explanation:
In a terminating decimals, numbers get terminated after decimal like
1/4 = 0.25
while in repeating decimals, numbers get repeated after decimal like
1/3 = 0.33333
When we multiply two decimals which are repeating and terminating decimals the result will be a repeating decimal.
Therefore area of the rhombus will be a repeating decimal.
Answer:
It will always be true
Step-by-step explanation:
Answer:
4dogs and no wolves
Step-by-step explanation:
when a dog is taken care of (Trained) it could be let to run free in a definite region.
On a plane with one line we can place two dogs (one dog in each of the regions) and they will not fight as they will be separated by a line, and they will run free.
If we place three lines in general, then we would have four regions where 4 dogs can run free as they are separated by a line so as not to fight.
But for Wolves from the question it is deduced that: A wolf has to be caged all the time and no matter how well you train a wolve, it wont yield to instructions.
With these two, wolves wont be allowed on the plane at all.
Answer:
$8.00+$3.00+$3.00=$14.00
Step-by-step explanation:
