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3 years ago

Will give extra points to whoever solves this

Mathematics

1 answer:

Hatshy [7]3 years ago

3 0

Answer:

Step-by-step explanation:

As Angle 5 and Angle 4 form a linear pair, they are supplementary.

Hence,

$Hence,\\Angle\ 5\ +\ Angle\ 4\ =\ 180\\(3x+7)+(9x-43)=180\\12x+(-36)=180\\12x=180+36\\12x=216\\x=18\\\\Hence, Obtuse\ Angle\ UPS = Angle\ 4 + 90\\Hence,\\Obtuse\ Angle\ UPS\ = (3x+7)+90\\\\We\ know\ that\ x=18 \\Hence, Angle\ 4\ = (3*18+7)\\=(54+7)\\=61\\\\Obtuse\ Angle\ UPS\ = 61+90\\=151\\\\\\Reflex\ Angle\ UPS\ = 360-151\\=209$

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Question:

If a sample of 2 hammer is selected

(a) find the probability that all in the sample are defective.

(b) find the probability that none in the sample are defective.

Answer:

a $Pr = \frac{2}{110}$

b $Pr = \frac{72}{110}$

Step-by-step explanation:

Given

$n = 11$ --- hammers

$r = 2$ --- selection

This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities

Solving (a): Probability that both selection are defective.

For two selections, the probability that all are defective is:

$Pr = P(D) * P(D)$

$Pr = \frac{2}{11} * \frac{2-1}{11-1}$

$Pr = \frac{2}{11} * \frac{1}{10}$

$Pr = \frac{2}{110}$

Solving (b): Probability that none are defective.

The probability that a selection is not defective is:

$P(D') = \frac{9}{11}$

For two selections, the probability that all are not defective is:

$Pr = P(D') * P(D')$

$Pr = \frac{9}{11} * \frac{9-1}{11-1}$

$Pr = \frac{9}{11} * \frac{8}{10}$

$Pr = \frac{72}{110}$

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3 years ago

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Answer:

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Answer:

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Answer:

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