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umka21 [38]
3 years ago
8

A chemical refinery needs a vat. They want the vat to be a rectangular prism (with square bases) that has a maximum volume of 1,

000 cubic feet. They want to have it constructed to use the least amount of material. What should the lengths of the bases and sides be? (Note: One of the bases is the lid.)
Mathematics
1 answer:
Alex17521 [72]3 years ago
7 0

Answer:

For least material to be used lengths of square base and sides = 10 units.

Step-by-step explanation:

Let the lengths of the square base and the sides = x feet, x feet and y feet

Area of the square base = x² feet

Volume of the rectangular prism = Area of the square base × Height

                                                      = x²y cubic feet

1000 = x²y

y = \frac{1000}{x^2} -------(1)

Material used in the prism = Surface area of the rectangular prism

                                            = 2(lb + bh + hl)

Here, h =  height of the prism

l = length of the base

w = Width of the base

Material to be used (S) = 2(xy + x² + xy) - Area of lid

                                  S = 2(x² + 2xy) - x²

                                  S = x² + 2xy

Now by substituting the value of y from equation (1),

S = x² + 2x(\frac{1000}{x^{2} })

  = x² + \frac{2000}{x}

For least amount of material used,

We will find the derivative of the given function and equate it to zero.

S' = 2x - \frac{2000}{x^{2} }

2x - \frac{2000}{x^{2} } = 0

2x³ = 2000

x³ = 1000

x = 10 feet

From equation (1),

y = \frac{1000}{(10)^2}

y = 10 feet

Therefore, for least amount of the material used lengths of square base and sides will be 10 feet.

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Given, PQ⊥PS,PQ∥SR,∠SQR=28

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According to the question,

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