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Andrei [34K]
3 years ago
15

Complete the questions below using the following diagram.

Chemistry
1 answer:
Vadim26 [7]3 years ago
5 0

Answer:

atomic number- 42

chemical number- 96

number of protons-18

atomic mass-96

number of eletrons-42

number of valence eletrons- 1, 2, 13, or 18. (sorry i forgot)

nummber of shells in n=3 shell-18

number of neutrons-54

Explanation:

well i just know the periodic table by heart and thats how i got the answer XD

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Answer is attached  below ( sorry for mistake )

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The answers please to this
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I know for number 4 the answer is c, sorry I can't help with the others.
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An igneous rock has a coarse texture and is dark in color. How else can this rock be accurately described?
skelet666 [1.2K]

Answer:

C,D.

Explanation:

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3 0
3 years ago
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A sample of gas has an initial pressure of 1.5 atm, an initial volume of 3.0 L, and an initial temperature of 293K. If the final
Nataliya [291]

Answer:

1.9 L

Explanation:

Step 1: Given data

  • Initial pressure (P₁): 1.5 atm
  • Initial volume (V₁): 3.0 L
  • Initial temperature (T₁): 293 K
  • Final pressure (P₂): 2.5 atm
  • Final volume (V₂): ?
  • Final temperature (T₂): 303 K

Step 2: Calculate the final volume of the gas

If we assume ideal behavior, we can calculate the final volume of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 1.5 atm × 3.0 L × 303 K / 293 K × 2.5 atm = 1.9 L

6 0
3 years ago
4. Find the pH at each of the following points in the titration of 25 mL of 0.3 M HF with 0.3 M NaOH. The Ka value is 6.6x10-4 a
yawa3891 [41]

Explanation:

Since HF is a weak acid, the use of an ICE table is required to find the pH. The question gives us the concentration of the HF.

HF+H2O⇌H3O++F−HF+H2O⇌H3O++F−

Initial0.3 M-0 M0 MChange- X-+ X+XEquilibrium0.3 - X-X MX M

Writing the information from the ICE Table in Equation form yields

6.6×10−4=x20.3−x6.6×10−4=x20.3−x

Manipulating the equation to get everything on one side yields

0=x2+6.6×10−4x−1.98×10−40=x2+6.6×10−4x−1.98×10−4

Now this information is plugged into the quadratic formula to give

x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)−−−−−−−−−−−−−−−−−−−−−−−−−−−−√2x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)2

The quadratic formula yields that x=0.013745 and x=-0.014405

However we can rule out x=-0.014405 because there cannot be negative concentrations. Therefore to get the pH we plug the concentration of H3O+ into the equation pH=-log(0.013745) and get pH=1.86

6 0
2 years ago
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