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Debora [2.8K]
3 years ago
13

Identify the quantum numbers for the electron gained when an F2 ion becomes an F3 ion

Chemistry
1 answer:
zhuklara [117]3 years ago
4 0

Answer: n= 3, l= 0 , m= 0 and s=[/tex]\frac{-1}{2}[/tex]

Explanation:

Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic quantum number :  It describes the orientation of the orbital. It is represented as 'm'. The value of m ranges from -l to +l.

Spin quantum number:  It describes the spin of the electron. It is represented as 's'. The value of s can be +1/2 or -1/2

F^{2-}:11: 1s^22s^22p^63s^1

F^{3-}:12:1s^22s^22p^63s^2

Thus electron enters 3s orbital , thus n= 3, l= 0 , m= 0 and s=[/tex]\frac{-1}{2}[/tex]

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Lostsunrise [7]

Answer:

2Mg  +  O2 →  2MgO

Explanation:

In all conbustion you should know, that reactans are an specific compound and O2, so the products must be CO2 and H2O, or in this case, the corresponding oxide.

6 0
3 years ago
piece of copper iron silver and gold are dropped into a solution of iron sulphate the piece that will get a coating of a copper
torisob [31]

Pieces of copper, silver and gold are dropped into a solution of iron sulphate. The piece that will get a coating of copper is. ... Therefore, none of the three metals can displace iron from its salt solution. Hence, we observe that no reaction takes place and none of the pieces get coated.

5 0
3 years ago
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What is the value for AG at 5000 K if AH = -220 kJ/mol and S= -0.05 kJ/(mol-K)?
Serhud [2]

Answer:

C. 30 kJ

Explanation:

Hello there!

In this case, in agreement to the thermodynamic definition of the Gibbs free energy, in terms of enthalpy of entropy:

\Delta G= \Delta H-T\Delta S

It is possible to calculate the required G by plugging in the given entropy and enthalpy as shown below:

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4 0
2 years ago
If 1.27 moles of bromine gas (Br2) react with excess phosphorus (P), how many moles of phosphorus tribromide (PBr3) will be prod
frez [133]

Answer:

0.85 mole of PBr3.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

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From the balanced equation above,

3 moles of Br2 reacted to produce 2 moles of PBr3.

Therefore, 1.27 moles of Br2 will react to produce = (1.27 x 2)/ 3 = 0.85 mole of PBr3.

Therefore, 0.85 mole of PBr3 is produced by the reaction.

8 0
3 years ago
What is the average Volume of a single penny from the total 25 penny data?
mojhsa [17]

Answer:

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3 years ago
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