T₁ = 27°C = 27 + 273 = 300K, V₁ = 6 L,
T₂ = 150°C = 150 + 273 = 423K, V₂ = ?,
By Charles' Law: V₁/T₁= V₂/T₂
6/300 = V₂/423
423*(6/300) = V₂
8.46 = V₂
Volume at 150°C =8.46 L.
Gas<span> molecules </span>diffuse more<span> quickly </span>than<span> liquid and solid molecules </span>because<span> there is</span>more<span> free space between </span>gas<span> molecules, which gives them </span>more<span> room to move. This causes the molecules to bounce against each other and increases the rate of diffusion. The molecules in liquid are much closer together </span>than<span> those in </span>gas<span>.</span>
A solution contains 12 g of glucose in 240 mL of solution. What is the mass/volume % of the solution? 5.0% (m/v). Calculate the grams of KCl in 225 g of an 8.00 % (m/m) KCl solution
When pure HA is added to the buffer, the buffer component ratio and the pH decrease.
<h3>State and explain the relative change in the pH and in the buffer-component concentration ratio, [NaA]/[HA] for the dissolve of pure HA in the buffer.</h3>
When pure HA is added to the buffer, the buffer component ratio and the pH decrease. The added HA increases the concentrations of NA and HA. However, there is a greater relative increase in the concentration of HA. Hence, the ratio of [NaA]/[HA] decreases, causing the solution to become more acidic.
The capacity of a buffer to withstand pH change is measured. The concentration of the buffer's components namely, the acid and its conjugate base determine this ability. Greater buffer capacity is associated with higher buffer concentration.
To learn more about buffer-component, Visit:
brainly.com/question/9542245
#SPJ4
