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3 years ago

A stone is dropped from a high tower and 9.21 seconds later it hits the ground. How high is the tower?

Physics

1 answer:

mrs_skeptik [129]3 years ago

4 0

Answer:

S = 415.64m

Explanation:

Given the following data;

Time, t = 9.21secs

Since it's a free fall, acceleration due to gravity = 9.8m/s²

Initial velocity, u = 0

To find the height of the tower, we would use the second equation of motion;

$S = ut + \frac {1}{2}at^{2}$

Where;

S represents the displacement or height measured in meters.

u represents the initial velocity measured in meters per seconds.

t represents the time measured in seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

$S = 0*9.21 + \frac {1}{2}*(9.8)*9.21^{2}$

$S = 0 + 4.9*84.8241$

$S = 4.9*84.8241$

Height, S = 415.64m

Therefore, the tower is 415.64m in height.

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A bridge is constructed above a river such that an object dropped from it will reach the river after 4.5 seconds. A precocious y

Sloan [31]

Answer:

Vf = 11.04 m/s

Explanation:

First, we consider free fall motion with zero initial velocity. Using 2nd equation of motion:

h = Vi t + (1/2)gt²

where,

h = height of bridge = ?

Vi = Initial Speed = 0 m/s

t = time taken = 4.5 s

g = 9.8 m/s²

Therefore,

h = (0 m/s)(4.5 s) + (1/2)(9.8 m/s²)(4.5 s)²

Therefore,

h = 99.225 m

Now, we consider the forced motion when the youth throws the ball with some negative initial energy:

Vi = - Vi

t = 3 s

h = 99.225 m

Therefore,

99.225 m = - Vi(3 s) + (1/2)(9.8 m/s²)(3 s)²

Vi = (- 99.225 m + 44.145 m)/3 s

Vi = - 18.36 m/s

Now, we use this in 1st equation of motion for final velocity:

Vf = Vi + gt

Vf = -18.36 m/s + (9.8 m/s²)(3 s)

Therefore,

Vf = 11.04 m/s

7 0

4 years ago

A research van de graaff generator has a 2.30 m diameter metal sphere with a charge of 1.10 mc on it. (a) what is the electric p

juin [17]

The potential on the surface of the charged sphere is 3.9 × 10⁷ volts.

Given:

The diameter of the sphere is 2.30 m and the charge of 1.10 mc.

The potential on the surface of a charged sphere is given by,

$V=k\frac{Q}{R}$

Where V is the potential on the surface, Q is the charge, R is the radius and k is the Coulomb's constant.

V = 8.99×10⁹×5×10⁻³/(2.30÷2)

V = 3.9 × 10⁷ volts

To learn more about van de graaff generator: brainly.com/question/9987015

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7 0

2 years ago

How far will a car travel in 25 seconds at 10m/ min

Kryger [21]

Time = 25s
speed = 10m/min
= 10m / 60
= (1/6)m/s

distance = speed × time
= 25 × (1/6)
=4.167m

7 0

4 years ago

A fixed system of charges exerts a force of magnitude 18 n on a 9.0 c charge. the 9.0 c charge is replaced with a 4.0 c charge.

laila [671]

According to the law of gravitational force:
the force between any two objects is directly proportional to the masses of the objects and inversely proportional to the square of the distance between these two objects.

Based on this:
if a 9 c charge is replaced with a 4 c charge while the distance between the charges is kept constant:
18/9 = F/4
2 = F/4
F = 2 x 4 = 8

7 0

3 years ago

Explain what you think is happening in this picture

Dima020 [189]

Answer:

sorry, there is no picture, try re-uploading it with the pic

Explanation:

5 0

3 years ago