Answer:
90 J
Explanation:
Change in potential energy when the spring is stretched
ΔU = ∫[(F) dx]................... Equation 1
Where F = 40x-6x²
Substitute into equation 1
ΔU = ∫[40x-6x²]
ΔU = [40x²/2 + 6x³/3 +C]
ΔU = [20x²+2x³ +C]
If the spring is stretch from x = 0m to x = 2m
ΔU = [20×2²+2×2³+C]-[20×0²+2×0³+C]
ΔU = [80+16+C]-[C]
ΔU = 90 J.
Hence the change in potential energy of the spring = 90 J
Answer:
β = 88°
Explanation:
Given,
Angle between the mirror, α = 46.0 °
Let 'i' and 'r' be the angle made with mirror by incident and reflected ray respectively.
Now,
α + i + r = 180°
i + r = 180°-46°
i + r = 134°
we know, angle of incidence and angle of reflection are equal.
Let β be the required angle
β + (180°-2i) + (180°-2r) = 180°
β -2(i+r) = -180
β = -180° + 2 x 134°
β = 88°
Hence, the angle between them is equal to 88°.
I am pretty sure it's solids
Answer:
Explanation:
Atmospheric pressure = 7 x 10⁴ Pa
force on a disk-shaped region 2.00 m in radius at the surface of the ocean due to atmosphere = pressure x area
= 7 x 10⁴ x 3.14 x 2 x 2
= 87.92 x 10⁴ N
b )
weight, on this exoplanet, of a 10.0 m deep cylindrical column of methane with radius 2.00 m
Pressure x area
height x density x acceleration of gravity x π r²
= 10 x 415 x 6.2 x 3.14 x 2 x 2
=323168.8 N
c ) Pressure at a depth of 10 m
atmospheric pressure + pressure due to liquid column
= 7 x 10⁴ + 10 x 415 x 6.2 ( hρg)
= 7 x 10⁴ + 10 x 415 x 6.2
(7 + 2.57 )x 10⁴ Pa
9.57 x 10⁴ Pa