Answer:
Vf = 11.04 m/s
Explanation:
First, we consider free fall motion with zero initial velocity. Using 2nd equation of motion:
h = Vi t + (1/2)gt²
where,
h = height of bridge = ?
Vi = Initial Speed = 0 m/s
t = time taken = 4.5 s
g = 9.8 m/s²
Therefore,
h = (0 m/s)(4.5 s) + (1/2)(9.8 m/s²)(4.5 s)²
Therefore,
h = 99.225 m
Now, we consider the forced motion when the youth throws the ball with some negative initial energy:
Vi = - Vi
t = 3 s
h = 99.225 m
Therefore,
99.225 m = - Vi(3 s) + (1/2)(9.8 m/s²)(3 s)²
Vi = (- 99.225 m + 44.145 m)/3 s
Vi = - 18.36 m/s
Now, we use this in 1st equation of motion for final velocity:
Vf = Vi + gt
Vf = -18.36 m/s + (9.8 m/s²)(3 s)
Therefore,
<u>Vf = 11.04 m/s</u>
The potential on the surface of the charged sphere is 3.9 × 10⁷ volts.
Given:
The diameter of the sphere is 2.30 m and the charge of 1.10 mc.
The potential on the surface of a charged sphere is given by,

Where V is the potential on the surface, Q is the charge, R is the radius and k is the Coulomb's constant.
V = 8.99×10⁹×5×10⁻³/(2.30÷2)
V = 3.9 × 10⁷ volts
To learn more about van de graaff generator: brainly.com/question/9987015
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Time = 25s
speed = 10m/min
= 10m / 60
= (1/6)m/s
distance = speed × time
= 25 × (1/6)
=4.167m
According to the law of gravitational force:
the force between any two objects is directly proportional to the masses of the objects and inversely proportional to the square of the distance between these two objects.
Based on this:
if a 9 c charge is replaced with a 4 c charge while the distance between the charges is kept constant:
18/9 = F/4
2 = F/4
F = 2 x 4 = 8
Answer:
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Explanation: