What is the terminal velocity of a penny falls off a skyscraper
1 answer:
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Answer:
A. .
Explanation:
By definition of Electric Capacitance, the capacitance of the system (), in farads, is described by the following formula:
(1)
Where:
- Electric charge, in coulombs.
- Voltage, in volts.
If we know that and
, then the capacitance of the system is:
The correct answer is A.
Complete question:
The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and the process is reversible and adiabatic. Use constant specific heat at 300 K to find the exit velocity.
Answer:
The exit velocity is 629.41 m/s
Explanation:
Given;
initial temperature, T₁ = 1200K
initial pressure, P₁ = 150 kPa
final pressure, P₂ = 80 kPa
specific heat at 300 K, Cp = 1004 J/kgK
k = 1.4
Calculate final temperature;
k = 1.4
Work done is given as;
inlet velocity is negligible;
Therefore, the exit velocity is 629.41 m/s
Explanation:
Formula for steady flow energy equation for the flow of fluid is as follows.
Now, we will substitute 0 for both and
, 0 for w, 334.9 kJ/kg for
, 2726.5 kJ/kg for
, 5 m/s for
and 220 m/s for
.
Putting the given values into the above formula as follows.
q = 6597.711 kJ
Thus, we can conclude that heat transferred through the coil per unit mass of water is 6597.711 kJ.