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balandron [24]
3 years ago
14

Which of the following represents "the square of the sum of a number and 4 is 36"?

Mathematics
1 answer:
Sedbober [7]3 years ago
8 0

Answer:

x^2+4 = 36

Step-by-step explanation:

the square of the sum of a number and 4

x^2+4

is means equals

x^2+4 = 36

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Amy, Bruce and Carlos collected a total of 168 pounds of cans to recycle. Bruce collected 1/3 the number of pounds of cans Carlo
disa [49]
A + b + c = 168
b = 1/3c
a = b + c....a = 1/3c + c = 4/3c

now we sub
4/3c + 1/3c + c = 168
8/3c = 168
c = 168 * 3/8
c = 504/8
c = 63 <=== Carlos collected 63 lbs

a = 4/3c
a = 4/3(63)
a = 252/3
a = 84 <== Amy collected 84 lbs

b = 1/3c
b = 1/3(63)
b = 63/3 <== Bruce collected 21 lbs
b = 21

3 0
3 years ago
In the diagram, what is the measure of angle 1?
grin007 [14]
3X+9X=180
12X=180
X=15°
Angle 1=3X
Angle 1 =45°
That's your answer.
5 0
3 years ago
Read 2 more answers
Select the correct answer. A model rocket was launched from the top of a building. The rocket's approximate height can be modele
garri49 [273]

Answer:

13 seconds.

Step-by-step explanation:

Given

h = -4.9(t - 13)(t + 2).

Required

Determine a reasonable solution for t

To do this, we equate h to 0.

h = -4.9(t - 13)(t + 2). becomes

0 = -4.9(t - 13)(t + 2).

Divide through by -4.9

0 = (t - 13)(t + 2).

Reorder the expression

(t - 13)(t + 2) = 0.

Split

t-13 = 0 or t + 2 = 0

This gives:

t = 13 or t = -2

But time can't be negative, So:

t = 13

6 0
2 years ago
What is the area of this triangle?
Diano4ka-milaya [45]

ANSWER

56.1 square inches.

EXPLANATION

The area of this triangle can be calculated using the formula,

Area =  \frac{1}{2} ab \sin( C)

where a=8in.

b=14.2 in.

and C=99° is the included angle.

We plug in these values to obtain,

Area =  \frac{1}{2} \times  8 \times 14.2 \sin( 99 \degree)

Area = 56.1007

We round to the nearest tenth to get,

56.1 sq. inch

6 0
3 years ago
Find the values of the constants p and q if the lines px + 5y = 7 and
Igoryamba

Answer:

2/5

Step-by-step explanation:

6 0
3 years ago
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