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Harrizon [31]
3 years ago
8

15. P(-3, 14). Q(2, -1), R(4,8), S(-2.-10) Types of lines m(PQ) -3 m(s) 3 neither

Mathematics
1 answer:
Natasha2012 [34]3 years ago
8 0

Answer:

75

Step-by-step explanation:

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The measure of an angle is 173°. What is the measure of its supplementary angle?
barxatty [35]

Answer:

7

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Help ASAP Jake took out an interest-free loan of $2,401.56 from the bank to buy a car. He paid the bank $200.13 each month until
Bezzdna [24]

Answer:

<em>Answer: D. Jake paid his loan in 12 months</em>

Step-by-step explanation:

Jake took out an interest-free loan of $2,401.56 from the bank to buy a car.

Since he has to pay no interest for the loan, the monthly payments are totally used to cover the amount of the loan.

He paid the bank $200.13 each month, thus the total months needed to pay the loan is:

\frac{\$2,401.56 }{\$200.13}=12

Answer: D. Jake paid his loan in 12 months

6 0
3 years ago
In triangle ABC , M and N are midpoints of sides. If MN = 2x + 5 and BC = x2 − 2, find the possible lengths for MN.
Karo-lina-s [1.5K]

Answer:

A.17

Step-by-step explanation:

3 0
3 years ago
The contents of a sample of 26 cans of apple juice showed a standard deviation of 0.06 ounces. We are interested in testing to d
NikAS [45]

Answer:

Option b. should not be rejected

Step-by-step explanation:

We are given that the contents of a sample of 26 cans of apple juice showed a standard deviation of 0.06 ounces.

We have to test whether the variance of the population is significantly more than 0.003, i.e.;

  Null Hypothesis, H_0 : \sigma = \sqrt{0.003}

Alternate Hypothesis, H_1 : \sigma > \sqrt{0.003}

The test statistics used here for testing variance is;

          T.S. = \frac{(n-1)s^{2} }{\sigma^{2} } ~ \chi^{2}__n_-_1

where, s = sample standard deviation = 0.06

           n = sample size = 26 cans

So, Test statistics = \frac{(26-1)0.06^{2} }{0.003 } ~ \chi^{2}__2_5

                            = 30

So, at 5% level of significance chi square table gives critical value of 37.65 at 25 degree of freedom. Since our test statistics is less than the critical so we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that null hypothesis should not be rejected and variance of population is 0.003.

5 0
3 years ago
I need this answered please
TiliK225 [7]
The answers are

1: False
2: True
3: True
4: False
4 0
2 years ago
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