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3 years ago

Which statement explains why spontaneous generation is a mistaken idea?

Chemistry

1 answer:

IceJOKER [234]3 years ago

8 0

Your answer is D; Not all living things can maintain homeostasis.

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One example of matter is

zaharov [31]

One example of matter could be Light.

6 0

3 years ago

Read 2 more answers

A sample of He gas (3.0 L) at 5.6 atm and 25°C was combined with 4.5 L of Ne gas at 3.6 atm and 25°C at constant temperature in

In-s [12.5K]

Answer:

3.6667

Explanation:

For helium gas:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 3.0 L

V₂ = 9.0 L

P₁ = 5.6 atm

P₂ = ?

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${5.6}\times {3.0}={P_2}\times {9.0} atm$

${P_2}=\frac {{5.6}\times {3.0}}{9.0} atm$

${P_1}=1.8667\ atm$

The pressure exerted by the helium gas in 9.0 L flask is 1.8667 atm

For Neon gas:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 4.5 L

V₂ = 9.0 L

P₁ = 3.6 atm

P₂ = ?

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${3.6}\times {4.5}={P_2}\times {9.0} atm$

${P_2}=\frac {{3.6}\times {4.5}}{9.0} atm$

${P_1}=1.8\ atm$

The pressure exerted by the neon gas in 9.0 L flask is 1.8 atm

Thus total pressure = 1.8667 + 1.8 atm = 3.6667 atm.

6 0

3 years ago

8. A party-supply store sells a helium-gas

MatroZZZ [7]

Answer:

P₂= 116.7 atm

Explanation:

Here apply the Boyle's law equations that states :at constant temperature the volume of a dry mass of a gas is inversely proportional to its pressure.

This is simplified as;

P₁V₁=P₂V₂ where P is pressure and V is volume

Given that;

P₁=1

V₁=1.81 m³

P₂=?

V₂=1.55*10^-2 m³

Apply the formula

1*1.81 =P₂*1.55*10^-2 m³

1.81/1.55*10^-2 =P₂

P₂= 116.7 atm

7 0

3 years ago

Which element exhibits a crystalline structure at STP? 1)F 2)CI 3)Br 4) I

umka21 [38]

It would be F only because I wouldn’t make sense CI doesn’t exhibit crystalline neither does BR so F

6 0

3 years ago

2. How much force, in g cm / s2 , is exerted by a golf ball described in problem 1 striking a tree while accelerating at 20 cm /

Lana71 [14]

Answer:

F = 1000 g cm/s²

Explanation:

Let the weight of 1 ball is 50 gram

Acceleration, a = 20 cm/s²

We need to find the force exerted by a golf ball. We know that,

F = ma

So,

F = 50 g × 20 cm/s²

F = 1000 g cm/s²

So, the required force is 1000 g cm/s².

5 0

3 years ago