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sladkih [1.3K]
3 years ago
9

Which of the following measurements is a little more than 3 feet?

Mathematics
2 answers:
Dima020 [189]3 years ago
7 0

meter I guess Is the correct answer

GuDViN [60]3 years ago
6 0

Answer:

A meter is approximately 3.28 feet.

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What is tan 30°?<br> 60'<br> 2<br> 1<br> 90<br> 30"
Lemur [1.5K]

Answer:

Option F. 1/√3

Step-by-step explanation:

From the question given above, the following data were obtained:

Angle θ = 30°

Opposite = 1

Adjacent = √3

The value of Tan 30° can be obtained as illustrated below:

Tan θ = Opposite / Adjacent

Tan 30 = 1/√3

Thus, the value of Tan 30° is 1/√3

8 0
2 years ago
Factor 8x^5+4x^2−12
Effectus [21]
D) because only 4 is the common factor in the equation.
4 0
3 years ago
Read 2 more answers
Twenty-seven is<br>% of 60<br>help mee asap​
jok3333 [9.3K]

Answer:  The answer is:  " <u> </u><u>45 </u>  % "  .    

________________________________________________

               →    " Twenty-seven is <u> 45 </u> % of 60. "

________________________________________________

Step-by-step explanation:

________________________________________________

The question asks:

 " 27 is what % {percentage] of 60 " ?  ;

________________________

So:  " 27 =  (n/100) * 60 " ;  Solve for "n" ;

________________________________________________

Method 1:

________________________________________________

  →   (n/100) * 60 = 27 ;

Divide each side by 60 :

 →   [ (n/100)  * 60 ] / 60 = 27 /60 ;

to get:

 →    (n/100) = 27/60 ;

Now:  Cross-factor multiply:

 →  60n = (27)*(100) ;

to get:

 → 60n = 2700 ;

Divide each side by "60" ;

→  60n = 2700/ 60 ;

to get:  n = 45 ;

________________________

 →  The answer is:  45 % .    

   →  " Twenty-seven is <u>45 %</u> of 60."

________________________________________________

Method 2:

________________________________________________

The question asks:

 " 27 is what % {percentage] of 60 " ?

________________________

To solve this problem:

Rephrase this question as:

________________________

" 27 is 60% of what number ? "

 →  The answer will be the same!

________________________

→  27 = (60/100)* n ;   Solve for "n" ;

Multiply each side of the equation by "100" ; to eliminate the fraction:

→  100 * 27 = 100 * [ (60/100)* n ] ;

 to get:

   →   2700 = 60n ;

↔  60n = 2700 ;

Divide Each Side of the equation by "60" ;

    →   60n/60 = 2700 / 60 ;

to get:  n = 45 ;

________________________________________________

→  The answer is:  45 % .    

       →  " Twenty-seven is <u>45 %</u> of 60."

________________________________________________

Method 2:  Variant 1 of 2:

________________________________________________

When we have:

→  27 = (60/100)* n ;   Solve for "n" ;

________________________

Note that:  "(60/100) = (60÷ 100) = (6 ÷ 10)" ;   since:  in "(60/100)" ;  the "zero" from the "<u>numerator</u>" cancels out;  <u>And</u>:  the "last zero" in "100" — from the "<u>denominator</u>" cancels out;  since we are dividing "each side" of the fraction by "10" ;

  →   "(60÷10) / (600÷10)"  =  " 6/10 " ;  

  →   " (6/10)" ; that is;  "six-tenths"} ;  

  →     can be represented by:  " 0.6 " ;

  →  {by convention;  but specifically, here is the explanation} — as follows:

________________________

  →   "(6/10)" =  " (6 ÷ 10) " ;  

<u>Note</u>:  When dividing a number by "10" ;  we take the original number; and move the decimal point to the left; & then we rewrite that number as the "answer".  

<u>Note</u>:  When multiplying or dividing by a positive, non-zero integer factor of "10" that has at least 1 (one) "zero" after that particular factor of "10".  We can get the answer by taking the original number & moving the decimal point the number of spaces as designated by the number of zeros following the particular [aforementioned factor of "10".].

We move the decimal point to the right if we are multiplying;  and to the left  if we are dividing.  In this case, <u>we are dividing</u> "6" by "10 " :

 →  " 6   ÷  10  =  ? " ;  

 →  " 6.  ÷ 10 =  ? " ;

   We take the: " 6. " ;  and move the decimal point "<u>one space backward [i.e. "to the left</u>"];  since we are <u>dividing by "</u><u>10</u><u>"</u> ;

 →  to get:  " .6 " ;  & we rewrite this value as "0.6" in a rewritten equation:

________________________

So; we take our equation:

→  27 = (60/100)*n ;  And rewrite—substituting "0.6" for

"(60/100)"— as follows:

________________________

→  27 = (0.6)n ;  ↔ (0.6) n = 27 ;

Multiply each side of the equation by "10" ; to eliminate the decimal:

   →  10 * [ (0.6)n ]  = 27 * 10 ;

to get:

  →  6n = 270 ;

Divide each side of the equation by "6" ; to isolate "n" on one side of the equation; & to solve for "n" ;

 →  6n / 6  =  270 / 6 ;

to get:   n = 45 ;

________________________________________________

→  The answer is:  45 % .    

      →  " Twenty-seven is <u>45 %</u> of 60."

________________________________________________

Method 2 (variant 2 of 2):

________________________________________________

We have the equation:  27 = (60/100)* n ;   Solve for "n" ;

________________________

<u>Note</u>:  From Method 2 (variant) 1 of 2— see above):

________________________

<u>Note</u>:  Refer to the point at which we have:

________________________

→   " {  (60÷10) / (600÷10)"  =  " (6/10) " ;  that is;  "six-tenths"} ;

________________________

Note that the fraction— "(6/10)" ;  can be further simplified:

→  "(6/10)" =  "(6÷2) / (10÷2)" = "(3/5)" ;

Now, we can rewrite the equation;

→ We replace "(60/100)" ;  with:  "(3/5)" :

    →  27 = (3/5)* n ;   Solve for "n" ;

↔ (3/5)* n = 27 ;  

↔    (3n/5) = 27 ;

Multiply Each Side of the equation by "5" ;

→  5* (3n/5) = 27 * 5 ;  

to get:

→   3n = 135 ;

Divide Each side of the equation by "3" ;  to isolate "n" on one side of the equation;  & to solve for "n" ;

→  3n / 3 = 135 / 3  ;

to get:   n = 45 ;

________________________________________________

 →  The answer is:  45 % .    

       →  " Twenty-seven is <u>45 %</u> of 60."

________________________________________________

Hope this answer is helpful!

        Wishing you the best in your academic endeavors

           — and within the "Brainly" community!

________________________________________________

7 0
3 years ago
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Please Help Can weather and climate be used interchangeably.
pickupchik [31]

Answer:

yes

'Weather' and 'climate' are used interchangeably.

Step-by-step explanation:

"Climate" describes the average atmospheric conditions over many years

the average annual rainfall, the predominant wind direction, or the season in which rain is likely to occur can be said as  Weather

<h2><u><em>hope it helps u</em></u></h2><h2><u><em>if it does so please mark me as brainiest </em></u></h2>
8 0
3 years ago
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Area A, equals the product of b and h divided by 2, slove for h
gizmo_the_mogwai [7]
A = bh/2
2a = bh
2a/b = h

h = 2a/b
7 0
3 years ago
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