Since there are more parakeets than canaries, it is not possible to have only 1 of each bird in each cage <u>and</u> have the same number of birds in each cage.
He could use 42 cages, putting a canary in with the parakeet in 18 of them. Then he would have 18 cages with 2 birds each, and 24 cages with 1 bird each.
The only way to have the same number of birds (1) in all cages is to have 60 cages, 42 of which have 1 parakeet, and 18 of which have 1 canary.
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If more than 1 of each kind of bird can be put in the cage, the collection of birds could be put into 6 cages, each of which would be home to 7 parakeets and 3 canaries.
Answer:
First option
h = 4 and k = - 2
Step-by-step explanation:
f(x) = x^3 translated to g(x) = (x – h)^3 + k.
f(x) transformed to g(x) with 4 units to the right and 2 units down
g(x) = (x - 4)^3 - 2
h = 4 and k = - 2
Answer:
what?
Step-by-step explanation:
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Answer:
Step-by-step explanation:
We have the recursive formula of a sequence:
